Re: "But unable to understand, how can fast switching transistor result in less jitter as compared to slow switching transistor." There are probably better answers than this, but here's one way slower switching can result in higher jitter: If the voltage noise on the signal is greater than nothing, and that must be true, then slower transitions turn that voltage noise into larger time domain jitter. I don't know what you're looking at so here is a totally contrived example. Suppose there is just 3mV rms noise. That means in a short span of time there could be 10mV excursions. 3 sigma is not rare. Now, suppose we have transitions rising from 0 to 3V, one in 100ps, the other in 200ps. The slope of the first is 3V/100ps = 30e9V/s or 30V/ns. The slope of the second is 3V/200ps which of course is 15e9V/s or 15V/ns. So, suppose that as the transition is rising toward the threshold, sometimes a 10mV positive noise excursion makes it cross the threshold early. How much time shift could that cause? For the 100ps transition: 10mV / 30e9V/s = 0.333ps For the 200ps transition: 10mV / 15e9V/s = 0.667ps And similarly it could also happen that as the transition approaches the threshold a negative going noise excursion delays the time when the threshold is actually crossed. Summary: Voltage noise translates into timing jitter. The amount of jitter it causes is more for slower transitions (it is inversely proportional to the slope of the transition). --- Joe S. ------------------------------------------------------------------ To unsubscribe from si-list: si-list-request@xxxxxxxxxxxxx with 'unsubscribe' in the Subject field or to administer your membership from a web page, go to: //www.freelists.org/webpage/si-list For help: si-list-request@xxxxxxxxxxxxx with 'help' in the Subject field List forum is accessible at: http://tech.groups.yahoo.com/group/si-list List archives are viewable at: //www.freelists.org/archives/si-list Old (prior to June 6, 2001) list archives are viewable at: http://www.qsl.net/wb6tpu