[SI-LIST] Re: IBIS Ramp data
- From: Hithesh <hitheshn@xxxxxxxxx>
- To: SI-List <si-list@xxxxxxxxxxxxx>
- Date: Fri, 12 Oct 2012 22:24:27 +0530
Hi All,
Thanks for the reply.
I knew he IBIS specs. I did the 80-20% math. The numbers didn't add up. So
I posted.
The dv/dt example was for 1.8V Medium drive strength, 50 ohm load, taken
from SAM9G25 ibis (bpp1v8_md)
dv = 0.28, So total V is (0.28/0.6)=0.46. It's 50 ohms load, so x2 = 0.93v ?
Where am I going wrong.
-Hithesh
On Fri, Oct 12, 2012 at 9:45 PM, Tom Dagostino <tom@xxxxxxxxxxxxx> wrote:
> Hitesh
>
> The answer to your question is in the IBIS spec. The dV is voltage
> difference between the 20% and 80% values of the peak to peak swing of the
> output as loaded in the extraction of the VT waveform. The dT is the time
> difference between those two points. For a CMOS like output the falling
> ramp is from the falling waveform with a load terminated to Vdd and the
> rising is from the rising waveform whose load is terminated to ground.
>
> Tom Dagostino
>
> Teraspeed Labs
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> tom@xxxxxxxxxxxxx
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>
> -----Original Message-----
> From: si-list-bounce@xxxxxxxxxxxxx [mailto:si-list-bounce@xxxxxxxxxxxxx]
> On
> Behalf Of Hithesh
> Sent: Friday, October 12, 2012 8:12 AM
> To: SI-List
> Subject: [SI-LIST] IBIS Ramp data
>
> Basic question about ramp data specified in IBIS file - How is the ramp
> data
> specified?
> For example, if the dv/dt for 1.8v is 0.28/0.185n Are the dv and dt number
> random?
>
> Thanks,
> -Hithesh
>
>
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