[pythran] Re: dimension-independent functions?
- From: serge Guelton <sguelton@xxxxxxxxxxxxx>
- To: pythran@xxxxxxxxxxxxx
- Date: Fri, 5 Sep 2014 14:33:05 +0200
On Fri, Sep 05, 2014 at 08:28:36AM -0400, Neal Becker wrote:
> Thanks.
>
> Your version seems much more elegant
I thought you were benchamrking pythran :-)
> def sqrv(x):
> Â Â Â Â return x * x
>
> I didn't know pythran would produce an element-wise iteration over the whole
> array from this code.
That's valid numpy, nothing specific to Pythran.
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