Dirk, you took the words right out of my mouth.
olaf
On Mar 12, 2005, at 14:19, Dirk Bonne wrote:
Hi Ray,
when I ran your program I got a little different output than the one you copied pasted in your mail.
I had also to change the for loop in the gtrail (although it prints out trails going from 10 -> -25cm, the program uses -40 -> -48cm). With 10->-25 the values printed out get quite wierd (no self centering effect):
steerAngle 20.0 pivot ground trail 10 5 0 -5 -10 -15 -20 -25
40 -4.077 -3.532 -2.98 -2.421 -1.855 -1.281 -0.699 -0.111 41 -4.109 -3.562 -3.007 -2.444 -1.873 -1.295 -0.708 -0.114 42 -4.139 -3.589 -3.031 -2.466 -1.892 -1.31 -0.719 -0.12 43 -4.165 -3.614 -3.055 -2.487 -1.91 -1.325 -0.731 -0.129 44 -4.189 -3.637 -3.077 -2.507 -1.929 -1.342 -0.745 -0.14 45 -4.209 -3.658 -3.097 -2.527 -1.947 -1.359 -0.761 -0.153 46 -4.226 -3.675 -3.115 -2.545 -1.966 -1.376 -0.777 -0.168 47 -4.24 -3.69 -3.131 -2.562 -1.983 -1.394 -0.795 -0.185 48 -4.249 -3.702 -3.145 -2.578 -2.0 -1.412 -0.813 -0.204 49 -4.255 -3.711 -3.156 -2.591 -2.016 -1.43 -0.833 -0.224 50 -4.257 -3.716 -3.165 -2.604 -2.031 -1.447 -0.852 -0.246 51 -4.254 -3.718 -3.171 -2.614 -2.045 -1.465 -0.873 -0.269 52 -4.248 -3.717 -3.175 -2.622 -2.057 -1.481 -0.893 -0.293 53 -4.236 -3.711 -3.175 -2.627 -2.068 -1.497 -0.914 -0.319 54 -4.221 -3.702 -3.172 -2.631 -2.077 -1.512 -0.935 -0.344 55 -4.2 -3.689 -3.166 -2.631 -2.085 -1.526 -0.955 -0.371 56 -4.175 -3.671 -3.156 -2.629 -2.09 -1.539 -0.975 -0.398 57 -4.145 -3.649 -3.142 -2.624 -2.093 -1.55 -0.994 -0.424 58 -4.109 -3.623 -3.125 -2.616 -2.094 -1.559 -1.012 -0.451 59 -4.069 -3.592 -3.104 -2.604 -2.092 -1.567 -1.029 -0.478 60 -4.023 -3.557 -3.079 -2.589 -2.087 -1.572 -1.045 -0.504 61 -3.972 -3.517 -3.05 -2.571 -2.08 -1.576 -1.059 -0.529 62 -3.916 -3.471 -3.016 -2.548 -2.069 -1.577 -1.072 -0.554 63 -3.854 -3.421 -2.978 -2.522 -2.055 -1.575 -1.083 -0.577 64 -3.786 -3.366 -2.935 -2.493 -2.038 -1.571 -1.092 -0.599 65 -3.713 -3.306 -2.888 -2.458 -2.017 -1.564 -1.098 -0.619 66 -3.634 -3.241 -2.836 -2.42 -1.993 -1.554 -1.102 -0.638 67 -3.55 -3.17 -2.779 -2.378 -1.965 -1.54 -1.103 -0.654 68 -3.46 -3.094 -2.717 -2.33 -1.932 -1.523 -1.102 -0.668 69 -3.364 -3.012 -2.651 -2.279 -1.896 -1.503 -1.097 -0.68 70 -3.262 -2.925 -2.579 -2.222 -1.856 -1.478 -1.089 -0.689 71 -3.154 -2.832 -2.502 -2.161 -1.811 -1.45 -1.078 -0.695 72 -3.04 -2.734 -2.419 -2.095 -1.762 -1.418 -1.063 -0.698 73 -2.921 -2.631 -2.332 -2.024 -1.708 -1.381 -1.045 -0.698 74 -2.795 -2.521 -2.239 -1.948 -1.649 -1.34 -1.022 -0.694 75 -2.664 -2.406 -2.141 -1.867 -1.586 -1.295 -0.995 -0.686 76 -2.527 -2.286 -2.037 -1.781 -1.517 -1.245 -0.964 -0.675 77 -2.384 -2.16 -1.928 -1.69 -1.444 -1.191 -0.929 -0.659 78 -2.235 -2.028 -1.814 -1.593 -1.366 -1.131 -0.889 -0.639 79 -2.081 -1.89 -1.694 -1.491 -1.282 -1.067 -0.845 -0.615
To be able to compare, I adapted my program (octave). Here is the output of my program:
octave> flevo2 aa 10.0 5.0 0.0 -5.0 -10.0 -15.0 -20.0 -25.0 40.0 -0.26 -0.12 0.01 0.15 0.29 0.42 0.56 0.69 41.0 -0.26 -0.12 0.01 0.15 0.29 0.42 0.56 0.70 42.0 -0.26 -0.12 0.01 0.15 0.29 0.43 0.56 0.70 43.0 -0.26 -0.12 0.01 0.15 0.29 0.43 0.57 0.70 44.0 -0.26 -0.12 0.01 0.15 0.29 0.43 0.57 0.71 45.0 -0.26 -0.12 0.01 0.15 0.29 0.43 0.57 0.71 46.0 -0.26 -0.12 0.01 0.15 0.29 0.43 0.57 0.71 47.0 -0.26 -0.12 0.01 0.15 0.29 0.43 0.57 0.71 48.0 -0.26 -0.12 0.01 0.15 0.29 0.43 0.56 0.70 49.0 -0.26 -0.12 0.01 0.15 0.29 0.42 0.56 0.70 50.0 -0.26 -0.12 0.01 0.15 0.29 0.42 0.56 0.70 51.0 -0.25 -0.12 0.01 0.15 0.28 0.42 0.56 0.69 52.0 -0.25 -0.12 0.01 0.15 0.28 0.42 0.55 0.69 53.0 -0.25 -0.12 0.01 0.15 0.28 0.41 0.55 0.68 54.0 -0.25 -0.12 0.01 0.14 0.28 0.41 0.54 0.67 55.0 -0.25 -0.12 0.01 0.14 0.27 0.40 0.53 0.67 56.0 -0.24 -0.12 0.01 0.14 0.27 0.40 0.53 0.66 57.0 -0.24 -0.11 0.01 0.14 0.26 0.39 0.52 0.65 58.0 -0.24 -0.11 0.01 0.14 0.26 0.39 0.51 0.64 59.0 -0.23 -0.11 0.01 0.13 0.26 0.38 0.50 0.63 60.0 -0.23 -0.11 0.01 0.13 0.25 0.37 0.49 0.62 61.0 -0.22 -0.11 0.01 0.13 0.25 0.36 0.48 0.60 62.0 -0.22 -0.10 0.01 0.12 0.24 0.36 0.47 0.59 63.0 -0.21 -0.10 0.01 0.12 0.23 0.35 0.46 0.58 64.0 -0.21 -0.10 0.01 0.12 0.23 0.34 0.45 0.56 65.0 -0.20 -0.10 0.01 0.11 0.22 0.33 0.44 0.54 66.0 -0.20 -0.09 0.01 0.11 0.21 0.32 0.42 0.53 67.0 -0.19 -0.09 0.01 0.11 0.21 0.31 0.41 0.51 68.0 -0.18 -0.09 0.01 0.10 0.20 0.30 0.40 0.49 69.0 -0.18 -0.09 0.01 0.10 0.19 0.29 0.38 0.48 70.0 -0.17 -0.08 0.01 0.09 0.18 0.27 0.37 0.46 71.0 -0.16 -0.08 0.01 0.09 0.18 0.26 0.35 0.44 72.0 -0.16 -0.08 0.00 0.09 0.17 0.25 0.33 0.42 73.0 -0.15 -0.07 0.00 0.08 0.16 0.24 0.32 0.40 74.0 -0.14 -0.07 0.00 0.08 0.15 0.23 0.30 0.38 75.0 -0.13 -0.07 0.00 0.07 0.14 0.21 0.28 0.36 76.0 -0.13 -0.06 0.00 0.07 0.13 0.20 0.27 0.33 77.0 -0.12 -0.06 0.00 0.06 0.13 0.19 0.25 0.31 78.0 -0.11 -0.05 0.00 0.06 0.12 0.17 0.23 0.29 79.0 -0.10 -0.05 0.00 0.05 0.11 0.16 0.21 0.27
I think the calculation of the frontAxle* values is too simplified. msssHT.py uses a linear formula for that, but that makes a rather large error. Instead of:
k=steerAngle*2/pi
I would propose
k=1 - cos(steerAngle)
This has considarable effect. For example at 20degrees k is only 0.0603 instead of 0.222
The second problem is in the steerDropAngle. The correct formula is rather complicated. I switch to a matrix calculation here.
if you define the unrotated front wheel as [xt,yt,zt] =
[R*cos(t), 0, R*sin(t)] where t in [0, 2*pi[ and R is the front wheel radius
then the formula for the front wheel rotated in the new steering axle point would be (choke!):
[cos(HA)*cos(HA)*R*cos(t) + cos(SA)*(1-cos(HA)*cos(HA))*R*cos(t) -sin(HA)*cos(HA)*R*sin(t) + cos(SA)*sin(HA)*cos(HA)*R*sin(t),
-sin(SA)*sin(HA)*R*cos(t)- sin(SA)*cos(HA)*R*sin(t),
-cos(HA)*sin(HA)*R*cos(t) + cos(SA)*cos(HA)*sin(HA)*R*cos(t) + sin(HA)*sin(HA)*R*sin(t) + cos(SA)*(1-sin(HA)*sin(HA))*R*sin(t)]
where HA= headangle, SA is steerAngle
This formula follows from substituting the formulas at:
http://www.euclideanspace.com/maths/algebra/matrix/orthogonal/ rotation/
The minimum z would be at (follows out of the derivation of the z component in parameter t
tg(t) = ((sin(HA)*sin(HA) + cos(SA)*(1-sin(HA)*sin(HA))) / (cos(SA)*cos(HA)*sin(HA) - cos(HA)*sin(HA)))
This t you need to put back into the largish formula above to find the Z/X value of the lowest point of the wheel. This values can then be used to calculate the steerDropAngle.
As a test, I adapted your program (molested it actaully), but there are still a difference between the results. The new results of your program are here:
steerAngle 20.0 pivot ground trail 10 5 0 -5 -10 -15 -20 -25
40 -0.274 -0.137 0.0 0.138 0.276 0.415 0.555 0.694
41 -0.275 -0.138 0.0 0.139 0.278 0.418 0.558 0.698
42 -0.276 -0.138 0.0 0.139 0.279 0.419 0.56 0.701
43 -0.277 -0.139 0.0 0.14 0.28 0.421 0.562 0.703
44 -0.277 -0.139 0.0 0.14 0.28 0.421 0.563 0.705
45 -0.277 -0.139 0.0 0.14 0.28 0.421 0.563 0.705
46 -0.277 -0.139 0.0 0.14 0.28 0.421 0.562 0.705
47 -0.276 -0.138 0.0 0.14 0.279 0.42 0.561 0.703
48 -0.275 -0.138 0.0 0.139 0.278 0.419 0.559 0.701
49 -0.274 -0.137 0.0 0.138 0.277 0.416 0.557 0.698
50 -0.273 -0.137 -0.0 0.137 0.275 0.414 0.553 0.693
51 -0.271 -0.136 -0.0 0.136 0.273 0.411 0.549 0.689
52 -0.269 -0.135 -0.001 0.135 0.271 0.407 0.545 0.683
53 -0.266 -0.134 -0.001 0.133 0.268 0.403 0.539 0.676
54 -0.264 -0.133 -0.001 0.131 0.264 0.398 0.533 0.669
55 -0.261 -0.132 -0.001 0.129 0.261 0.393 0.526 0.66
56 -0.258 -0.13 -0.002 0.127 0.257 0.388 0.519 0.651
57 -0.254 -0.129 -0.002 0.125 0.253 0.381 0.511 0.641
58 -0.25 -0.127 -0.003 0.122 0.248 0.375 0.502 0.63
59 -0.246 -0.125 -0.003 0.12 0.243 0.368 0.493 0.619
60 -0.242 -0.123 -0.003 0.117 0.238 0.36 0.483 0.606
61 -0.237 -0.121 -0.004 0.114 0.233 0.352 0.472 0.593
62 -0.233 -0.119 -0.004 0.111 0.227 0.344 0.461 0.58
63 -0.227 -0.116 -0.005 0.108 0.221 0.335 0.45 0.565
64 -0.222 -0.114 -0.005 0.104 0.215 0.326 0.437 0.55
65 -0.216 -0.111 -0.006 0.101 0.208 0.316 0.425 0.534
66 -0.211 -0.109 -0.006 0.097 0.201 0.306 0.411 0.518
67 -0.205 -0.106 -0.007 0.093 0.194 0.295 0.397 0.5
68 -0.198 -0.103 -0.007 0.089 0.187 0.285 0.383 0.483
69 -0.192 -0.1 -0.008 0.085 0.179 0.273 0.368 0.464
70 -0.185 -0.097 -0.008 0.081 0.171 0.262 0.353 0.445
For lower pivot angles the results are now more or less the same as in my program, but at larger pivot angles there is a diviation. But at least the values that are output are sane now (negative trail give a rise at steering angle).
I haven't checked the reason for the deviation (and like i said it is not impossible that I am wrong. Calculating all this I find quite tricky).
Attached is the adapted program. Tip: you might have a look at quaternions. They simplify working in three dimensional space a great deal. AFAIK, there is a quaternion package in the python programming language.
cheers Dirk
mtb@xxxxxxxxxxxx: Hi Dirk,
Attached is the code I referred to. It uses Jürgen's newest P* geometry Attached also is a sketch I used as a guide. wheelBase = 72.5 steerAngle = 20. * math.pi / 180.0 rearMassZ = 28. rearMassX = 67. frontWheelRadius = 33. rearWheelRadius = 33.
The code tries to calculate the rise of the rear mass using a methodology I saw in one of the PDFs.
Some assumptions:
-a wheelie is a positive angle, the rear wheel is fixed and the frame rotates around it
-the rear frame does not lean
-turnAnglePnt is imaginary point the axle rotates about with steer,
is fixed with respect to rear frame, and is the center of a torus
swept by the wheel. It is on the pivot axis perpendicular to the front hub.
-all measurements are in the x-z plane
In the first part, measure the x-z change of the front hub as the rear frame is fixed and the pivot rotates. The front axle moves along the x-z plane with steer, sweeping through the torus. Then calc the angle between initial 0 steer, and current steer, relative to rear axle height; add any existing angle between axles. (If the front wheel was a point, this would definitely be the frame rise angle.)
Now, rotate the steer without mechanical trail holding frame fixed, and calc the low z point of the tire which change due to wheel flop. Calc angle due to steer -
max fWheel drop/flop is proportional to steer Angle==90
Subtract the angle the wheel drops due to flop, from the angle the frame rises due to the whole wheel sweeping about the center of the torus
Calc the angle from the rear mass to the rear axle.
Then:
newrearMassZ = rearWheelRadius+
rmass2Raxle*sin(rmass2RaxleAngle+frontAxleAngle-steerDropAngle)
If you see something I missed, please let me know! Each part checks out for the geometric extremes, steer=0,90,180, but the "peak rise" result differs from your reference frame vector method.
By the way, I saw a very good German bike site: http://www.kreuzotter.de/english/elenk.htm Maybe some of you know Walter Zorn?
Ray
sample rise output below.
steerAngle 20.0 ground trail pivot 10 5 0 -5 -10 -15 -20 -25 angle 40 5.753 5.862 5.971 6.081 6.191 6.301 6.411 6.521 41 5.787 5.898 6.008 6.119 6.23 6.341 6.452 6.564 42 5.817 5.928 6.04 6.151 6.263 6.375 6.488 6.6 43 5.841 5.953 6.066 6.178 6.291 6.404 6.518 6.631 44 5.86 5.973 6.086 6.2 6.313 6.427 6.541 6.656 45 5.874 5.988 6.102 6.216 6.33 6.445 6.559 6.674 46 5.883 5.997 6.112 6.226 6.341 6.456 6.571 6.687 47 5.887 6.001 6.116 6.231 6.346 6.461 6.577 6.693 48 5.885 6.0 6.114 6.23 6.345 6.461 6.577 6.693 49 5.878 5.993 6.108 6.223 6.338 6.454 6.57 6.687 50 5.865 5.98 6.095 6.21 6.326 6.442 6.558 6.674 51 5.848 5.962 6.077 6.192 6.307 6.423 6.539 6.655 52 5.824 5.939 6.053 6.168 6.283 6.398 6.514 6.63 53 5.796 5.909 6.023 6.138 6.252 6.367 6.483 6.598 54 5.762 5.875 5.988 6.102 6.216 6.33 6.445 6.56 55 5.723 5.835 5.947 6.06 6.174 6.287 6.401 6.516 56 5.678 5.789 5.901 6.013 6.125 6.238 6.351 6.465 57 5.628 5.738 5.849 5.96 6.071 6.183 6.295 6.408 58 5.573 5.682 5.791 5.901 6.011 6.121 6.232 6.344 59 5.513 5.62 5.728 5.836 5.945 6.054 6.164 6.274 60 5.447 5.553 5.659 5.766 5.873 5.981 6.089 6.198 61 5.376 5.48 5.585 5.69 5.796 5.902 6.008 6.115 62 5.3 5.403 5.506 5.609 5.713 5.817 5.922 6.027 63 5.22 5.32 5.421 5.522 5.624 5.726 5.829 5.932 64 5.134 5.232 5.331 5.43 5.53 5.63 5.731 5.832 65 5.044 5.14 5.236 5.333 5.43 5.528 5.626 5.725 66 4.949 5.042 5.136 5.231 5.325 5.421 5.517 5.613 67 4.849 4.94 5.031 5.123 5.215 5.308 5.401 5.495 68 4.745 4.833 4.922 5.011 5.1 5.19 5.281 5.372 69 4.637 4.722 4.808 4.894 4.981 5.068 5.155 5.243 70 4.524 4.606 4.689 4.772 4.856 4.94 5.025 5.11 71 4.408 4.487 4.566 4.646 4.727 4.808 4.889 4.971 72 4.287 4.363 4.439 4.516 4.593 4.671 4.749 4.827 73 4.163 4.236 4.308 4.382 4.455 4.529 4.604 4.679 74 4.035 4.104 4.174 4.243 4.313 4.384 4.455 4.526 75 3.905 3.97 4.035 4.101 4.168 4.234 4.302 4.369 76 3.77 3.832 3.894 3.956 4.018 4.081 4.145 4.208 77 3.633 3.691 3.749 3.807 3.866 3.925 3.984 4.044 78 3.494 3.547 3.601 3.655 3.71 3.765 3.82 3.875 79 3.351 3.401 3.45 3.5 3.551 3.602 3.653 3.704
At 08:56 AM 3/10/2005 +0100, you wrote:
Hi Ray,
OK, can you sent it to me (or better to the group). This weekend I should be able to look at it. Do note that it is not impossible that the error is on my side ;-)
It has been very busy on the list!!! I have only had the chance to look at what has been going on, without having the time to delve into the discussion. But I am looking forward to catch up with you guys!
Good stuff! Dirk
Ray Schümacher wrote:
Hello Dirk,
I had coded a short routine in Python to calculate rear mass rise, but I still get somewhat different results than yours. Might you have time to look at it and see if anything jumps out at you? I have an image as well, sketching out the geometry. I'll post them to the group if that would be helpful.
Cheers, Ray
<image.tiff>
#!/usr/bin/env python #Boa:PyApp:main
import math
modules ={}
def main():
wheelBase = 72.5 steerAngle = 20. * math.pi / 180.0 rearMassZ = 28. rearMassX = 67. frontWheelRadius = 33. rearWheelRadius = 33.
## calc angle from raxle to rmass, from horizontal
rmass2RaxleAngle = math.asin((rearMassZ-rearWheelRadius)/rearMassX)
## calc dist from raxle to rmass
rmass2Raxle = ((rearWheelRadius-rearMassZ)**2+rearMassX**2)**.5
## angle front to rear axle
## a wheelie is a pos+ angle
angleBtwnAxles = math.atan((frontWheelRadius-rearWheelRadius)/wheelBase)
print 'steerAngle', steerAngle/math.pi*180.0
print 'pivot ground trail '
print ' ', '\t10', '\t5', '\t0', '\t-5', '\t-10', '\t-15', '\t-20', '\t-25'
for angle in range(40, 80, 1):
headAngle = angle * math.pi / 180.0 # deg from horiz
print '\n',int(round(headAngle*180/math.pi)), ' ',
## iterate over the ground trail
for gtrail in range(-42, -50, -1):
mechTrail = frontWheelRadius*math.cos(headAngle) - gtrail*math.sin(headAngle)
## rear wheel does not move or roll, frame rotates around the axle
## turnAnglePnt is imaginary point the axle rotates about with steer,
## is fixed with respect to rear frame, and is the center of a torus
## swept by the wheel
turnAnglePntZ = frontWheelRadius+(math.cos(math.pi-headAngle)*mechTrail)#
turnAnglePntX = wheelBase-(math.sin(math.pi-headAngle)*mechTrail)#
turnAnglePnt2RearAxle = ((frontWheelRadius-turnAnglePntZ)**2+turnAnglePntX**2)**.5#
## front axle moves along the x-z plane with steer, sweeping through the torus
## steerAngle==pi at 180
frontAxleZ = frontWheelRadius-((steerAngle/math.pi)*2)*(math.sin(math.pi/2- headAngle)*mechTrail)#
frontAxleX = wheelBase-((steerAngle/math.pi)*2)*(math.sin(headAngle)*mechTrail)#
## angle between initial place, 0 steer, and current steer, frame not moved yet...
## relative to rear axle height; add any existing angle
frontAxleAngle = math.atan((rearWheelRadius-frontAxleZ)/frontAxleX)+angleBtwnAxles#
## now, rotate the steer, calc angle due to steer without trail - holding frame fixed
## max fWheel drop is prop. to steer Angle==90
steerDropAngle = math.asin( (math.sin(steerAngle)*math.cos(headAngle)*frontWheelRadius) / \
(wheelBase+math.sin(steerAngle)*math.cos(headAngle)*frontWheelRadius) )#
## subtract the amount the wheel drops due to flop, from the amount
## the frame rises due to the whole wheel sweeping about the center of the torus
## frontAxleAngle-steerDropAngle
## calc rearMassHeight
## so, hypotenous == rmass2Raxle
newrmass2RaxleAngle = rmass2RaxleAngle+frontAxleAngle-steerDropAngle#
newrearMassZ = rearWheelRadius+rmass2Raxle*math.sin(newrmass2RaxleAngle)#
#print '\t', round(newrearMassZ-rearMassZ, 2), #print '\t', round(rearPitchAngle/math.pi * 180.0, 2), #print ' ', round(frontAxle2Ground, 1), #print ' ', round(turnAnglePntZ, 1), print '\t', round(newrearMassZ-rearMassZ, 3),
if __name__ == '__main__': main()
<mime-attachment>#!/usr/bin/python #Boa:PyApp:main
import math
modules ={}
def main():
wheelBase = 72.5 steerAngle = 20. * math.pi / 180.0 rearMassZ = 28. rearMassX = 67. frontWheelRadius = 33. rearWheelRadius = 33.
## calc angle from raxle to rmass, from horizontal
rmass2RaxleAngle = math.asin((rearMassZ-rearWheelRadius)/rearMassX)
## calc dist from raxle to rmass
rmass2Raxle = ((rearWheelRadius-rearMassZ)**2+rearMassX**2)**.5
## angle front to rear axle
## a wheelie is a pos+ angle
angleBtwnAxles = math.atan((frontWheelRadius-rearWheelRadius)/wheelBase)
print 'steerAngle', steerAngle/math.pi*180.0
print 'pivot ground trail '
print ' ', '\t10', '\t5', '\t0', '\t-5', '\t-10', '\t-15', '\t-20', '\t-25'
for angle in range(40, 71, 1):
headAngle = angle * math.pi / 180.0 # deg from horiz
print '\n',int(round(headAngle*180/math.pi)), ' ',
## iterate over the ground trail
for gtrail in range(10, -30, -5):
# print "gtrail=", gtrail, "\n";
mechTrail = frontWheelRadius*math.cos(headAngle) - gtrail*math.sin(headAngle)
# print "mechTrail=", mechTrail, "\n";
## rear wheel does not move or roll, frame rotates around the axle
## turnAnglePnt is imaginary point the axle rotates about with steer,
## is fixed with respect to rear frame, and is the center of a torus
## swept by the wheel
turnAnglePntZ = frontWheelRadius+(math.cos(math.pi-headAngle)*mechTrail)#
turnAnglePntX = wheelBase-(math.sin(math.pi-headAngle)*mechTrail)#
turnAnglePnt2RearAxle = ((frontWheelRadius-turnAnglePntZ)**2+turnAnglePntX**2)**.5#
## front axle moves along the x-z plane with steer, sweeping through the torus
## steerAngle==pi at 180
frontAxleZ = -math.cos(headAngle)*mechTrail*(1 - math.cos(steerAngle))
frontAxleX = wheelBase - math.sin(headAngle)*mechTrail*(1 - math.cos(steerAngle))
# print "frontAxleZ=", frontAxleZ, "\n"
# print "frontAxleX=", frontAxleX, "\n"
## angle between initial place, 0 steer, and current steer, frame not moved yet...
## relative to rear axle height; add any existing angle
## now, rotate the steer, calc angle due to steer without trail - holding frame fixed
## max fWheel drop is prop. to steer Angle==90
SA=steerAngle
HA=headAngle
R=frontWheelRadius
cosHA=math.cos(HA)
sinHA=math.sin(HA)
cosSA=math.cos(SA)
sinSA=math.sin(HA)
t1=(sinHA*sinHA + cosSA*(1-sinHA*sinHA))
t2=(cosSA*cosHA*sinHA - cosHA*sinHA)
if(t2 == 0):
t=(-math.pi/2)
else:
t= math.atan(t1 / t2)
Z=-cosHA*sinHA*R*math.cos(t) + cosSA*cosHA*sinHA*R*math.cos(t) + sinHA*sinHA*R*math.sin(t) + cosSA*(1-sinHA*sinHA)*R*math.sin(t)
# print "Z=", Z, "\n";
X=frontAxleX-cosHA*cosHA*R*math.cos(t) + cosSA*(1-cosHA*cosHA)*R*math.cos(t) -sinHA*cosHA*R*math.sin(t) + cosSA*sinHA*cosHA*R*math.sin(t)
# print "X=", X, "\n";
combinedDropAngle = math.atan((R+frontAxleZ+Z)/X)
#steerDropAngle = math.asin( (math.sin(steerAngle)*math.cos(headAngle)*frontWheelRadius) / (wheelBase+math.sin(steerAngle)*math.cos(headAngle)*frontWheelRadius) )
## subtract the amount the wheel drops due to flop, from the amount
## the frame rises due to the whole wheel sweeping about the center of the torus
## frontAxleAngle-steerDropAngle
## calc rearMassHeight
## so, hypotenous == rmass2Raxle
newrmass2RaxleAngle = rmass2RaxleAngle-combinedDropAngle
newrearMassZ = rearWheelRadius+rmass2Raxle*math.sin(newrmass2RaxleAngle)#
#print '\t', round(newrearMassZ-rearMassZ, 2), #print '\t', round(rearPitchAngle/math.pi * 180.0, 2), #print ' ', round(frontAxle2Ground, 1), #print ' ', round(turnAnglePntZ, 1), print '\t', round(newrearMassZ-rearMassZ, 3),
if __name__ == '__main__': main()
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