RE: quick java question

  • From: "Suzanne Balik" <spbalik@xxxxxxxxxxxxxx>
  • To: programmingblind@xxxxxxxxxxxxx
  • Date: Thu, 29 Nov 2007 21:00:11 -0500 (EST)

You can use the Scanner class to do what you want to do easily, if you're
using Java 5.0. For example,

Scanner sc = new Scanner(System.in);
if (sc.hasNextInt())
  int value = sc.nextInt();



Suzanne Balik

NC State University      EB II 2318    (919)515-5617

We?ll take a cup o? kindness yet, for auld lang syne.
                                       --Robert Burns


> Do a search for
> Try catch tutorial
> Try statements and catch clauses are the way to go if you are going to
> seriously work with java.
>
>
> -----Original Message-----
> From: programmingblind-bounce@xxxxxxxxxxxxx
> [mailto:programmingblind-bounce@xxxxxxxxxxxxx] On Behalf Of Alex Parks
> Sent: Thursday, November 29, 2007 7:55 AM
> To: programmingblind@xxxxxxxxxxxxx
> Subject: RE: quick java question
>
>
> I am new to this language.  What do I put in place of "aString"
> and how do I use the exception in my if statement? Add a
> throwsException to the end? Thanks.
>
> Have a great day,
> Alex
>
>> ----- Original Message -----
>>From: "Sina Bahram" <sbahram@xxxxxxxxx
>>To: <programmingblind@xxxxxxxxxxxxx
>>Date sent: Thu, 29 Nov 2007 07:07:27 -0500
>>Subject: RE: quick java question
>
>>If you're expecting an integer, then you can do
>
>>Integer.parseInt(aString)
>
>>That will throw a NumberFormatException if it isn't a number.
>
>>Take care,
>>Sina
>
>
>>-----Original Message-----
>>From: programmingblind-bounce@xxxxxxxxxxxxx
>>[mailto:programmingblind-bounce@xxxxxxxxxxxxx] On Behalf Of Alex
> Parks
>>Sent: Thursday, November 29, 2007 12:51 AM
>>To: programmingblind@xxxxxxxxxxxxx
>>Subject: quick java question
>
>>Hi all,
>>Is there a quick way of determining if the user input is a
> number? I need it
>>to be a number; it throws an exception and exits the program if
> it isn't.
>>Maybe something like:
>>if (input!=\int
>>I have no idea about the syntax, but something along those lines
> is what I
>>am looking for.  Thanks for any help.
>
>>Have a great day,
>>Alex
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