RE: quick java question
- From: "Sina Bahram" <sbahram@xxxxxxxxx>
- To: <programmingblind@xxxxxxxxxxxxx>
- Date: Thu, 29 Nov 2007 07:07:27 -0500
If you're expecting an integer, then you can do
Integer.parseInt(aString)
That will throw a NumberFormatException if it isn't a number.
Take care,
Sina
-----Original Message-----
From: programmingblind-bounce@xxxxxxxxxxxxx
[mailto:programmingblind-bounce@xxxxxxxxxxxxx] On Behalf Of Alex Parks
Sent: Thursday, November 29, 2007 12:51 AM
To: programmingblind@xxxxxxxxxxxxx
Subject: quick java question
Hi all,
Is there a quick way of determining if the user input is a number? I need it
to be a number; it throws an exception and exits the program if it isn't.
Maybe something like:
if (input!=\int
I have no idea about the syntax, but something along those lines is what I
am looking for. Thanks for any help.
Have a great day,
Alex
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