Re: for loops without braces?
- From: Alex Midence <alex.midence@xxxxxxxxx>
- To: programmingblind@xxxxxxxxxxxxx
- Date: Fri, 19 Nov 2010 08:00:53 -0600
get MinGw and you'll have a nice c++ compiler for these sorts of things:
http://www.mingw.org/
Once you install it, add it to the path so gcc and g++ will work from
anywhere. Not having a compiler while studying c or c++ won't get you
very far.
Alex M
On 11/18/10, Alex Hall <mehgcap@xxxxxxxxx> wrote:
> Okay, thanks. Hopefully this will clear up Prim's Algorithm some. I
> would run it, but I do not have a C compiler; I use Python, and I
> think I have Java hanging around somewhere, but Python is my primary
> weapon of choice.
>
> On 11/18/10, Littlefield, Tyler <tyler@xxxxxxxxxxxxx> wrote:
>>
>> the print right under the for will be executed. As I said, it executes
>> the line right under it and no more. Whether that's an if statement
>> opening a new block or whatever. After the loop exits (after it prints
>> 0-9, the rest of your code will be executed. Try running it to see.
>> On 11/18/2010 8:19 PM, Dave wrote:
>>> or would only the first statement after the for, the print(i-1), be
>>> executed and then the loop exited?
>>>
>>> This is what would happen. Remember that only the statement/block
>>> after the loop would be parsed as the body of the loop. Without the
>>> braces, you'd only get the first print statement.
>>>
>>> On 11/18/10, Alex Hall<mehgcap@xxxxxxxxx> wrote:
>>>> Thanks for the quick responses. So, would the following be correct?
>>>>
>>>> for(i=0;i<10;i++)
>>>> print(i-1);
>>>> print(i+1);
>>>> if(i%2==0){
>>>> print(i);
>>>> }
>>>>
>>>> or would only the first statement after the for, the print(i-1), be
>>>> executed and then the loop exited?
>>>>
>>>> On 11/18/10, qubit<lauraeaves@xxxxxxxxx> wrote:
>>>>> easily -- when the compiler reaches the end of the statement following
>>>>> the
>>>>> )
>>>>> of the for loop header.
>>>>> Here the statement is the if statement, which could be huge and even
>>>>> contain
>>>>> an else clause, but according to C++ syntax, the compiler has to parse
>>>>> the
>>>>> complete statement before closing the for loop.
>>>>> --le
>>>>> ----- Original Message -----
>>>>> From: "Alex Hall"<mehgcap@xxxxxxxxx>
>>>>> To:<programmingblind@xxxxxxxxxxxxx>
>>>>> Sent: Thursday, November 18, 2010 8:09 PM
>>>>> Subject: for loops without braces?
>>>>>
>>>>>
>>>>> Hi all,
>>>>> I am desperately trying to understand Prim's algorithm. I have found
>>>>> it in pseudocode and C code, but in both examples they use for loops
>>>>> without braces, so it might be:
>>>>> for(i=0; i<4; i++)
>>>>> if(i%2==0){
>>>>> print(i);
>>>>> }
>>>>>
>>>>> Obviously this is understandable, but when you mix it into other code
>>>>> it becomes much harder to tell what is going on. First, how can one do
>>>>> this syntactically and have it be correct? Second, what is the rule to
>>>>> figure out where the loop ends if it is not in braces? The C compiler
>>>>> must have a way...
>>>>>
>>>>> --
>>>>> Have a great day,
>>>>> Alex (msg sent from GMail website)
>>>>> mehgcap@xxxxxxxxx; http://www.facebook.com/mehgcap
>>>>> __________
>>>>> View the list's information and change your settings at
>>>>> //www.freelists.org/list/programmingblind
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>>>>> __________
>>>>> View the list's information and change your settings at
>>>>> //www.freelists.org/list/programmingblind
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>>>>>
>>>>
>>>> --
>>>> Have a great day,
>>>> Alex (msg sent from GMail website)
>>>> mehgcap@xxxxxxxxx; http://www.facebook.com/mehgcap
>>>> __________
>>>> View the list's information and change your settings at
>>>> //www.freelists.org/list/programmingblind
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>>>>
>>> __________
>>> View the list's information and change your settings at
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>>>
>>
>>
>> --
>>
>> Thanks,
>> Ty
>>
>> __________
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>>
>
>
> --
> Have a great day,
> Alex (msg sent from GMail website)
> mehgcap@xxxxxxxxx; http://www.facebook.com/mehgcap
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>
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