RE: again a newbee question

  • From: "Sina Bahram" <sbahram@xxxxxxxxx>
  • To: <programmingblind@xxxxxxxxxxxxx>
  • Date: Wed, 13 Apr 2011 23:29:19 -0400

I don't see how that's the same thing though.

That's platform specific, no? i could be totally off on that point, but I 
thought it was.

This allows you to register 32 callbacks, and all your objects have destructors 
which get called by parents, etc, etc, so you should
be good to go.

Of course destructors of large object trees is a joke in C++, as anyone who has 
had to deal with multiple inherited classes and
destructor order resolution issues will tell you. throw in some virtual 
functions on top of that, and the only thing you'll be
destroying reliably is a bottle of something.

Take care,
Sina

-----Original Message-----
From: programmingblind-bounce@xxxxxxxxxxxxx 
[mailto:programmingblind-bounce@xxxxxxxxxxxxx] On Behalf Of Ken Perry
Sent: Wednesday, April 13, 2011 11:25 PM
To: programmingblind@xxxxxxxxxxxxx
Subject: RE: again a newbee question

I think Chris wants people to use the onDestroy stuff but in truth OnDestroy
is not going to free up nothing if the person doesn't' add the code to it so
I figure it doesn't matter either way.

Ken

-----Original Message-----
From: programmingblind-bounce@xxxxxxxxxxxxx
[mailto:programmingblind-bounce@xxxxxxxxxxxxx] On Behalf Of Sina Bahram
Sent: Wednesday, April 13, 2011 11:20 PM
To: programmingblind@xxxxxxxxxxxxx
Subject: RE: again a newbee question

Here:

void exit ( int status );

Terminates the process normally, performing the regular cleanup for
terminating processes.

First, all functions registered by calls to atexit are executed in the
reverse order of their registration. Then, all streams are
closed and the temporary files deleted, and finally the control is returned
to the host environment.

The status argument is returned to the host environment.

http://www.cplusplus.com/reference/clibrary/cstdlib/exit/

and here:

int atexit ( void ( * function ) (void) );
Set function to be executed on exit

The function pointed by the function pointer argument is called when the
program terminates normally.

If more than one atexit function has been specified by different calls to
this function, they are all executed in reverse order as a
stack, i.e. the last function specified is the first to be executed at exit.

One single function can be registered to be executed at exit more than once.

C++ implementations are required to support the registration of at least 32
atexit functions.

http://www.cplusplus.com/reference/clibrary/cstdlib/atexit/

take care,
Sina

-----Original Message-----
From: Sina Bahram [mailto:sbahram@xxxxxxxxx] 
Sent: Wednesday, April 13, 2011 11:17 PM
To: 'programmingblind@xxxxxxxxxxxxx'
Subject: RE: again a newbee question


I'd recommend looking up how exit works.

Take care,
Sina
-----Original Message-----
From: programmingblind-bounce@xxxxxxxxxxxxx
[mailto:programmingblind-bounce@xxxxxxxxxxxxx] On Behalf Of Christopher
Coale
Sent: Wednesday, April 13, 2011 11:06 PM
To: programmingblind@xxxxxxxxxxxxx
Subject: Re: again a newbee question

Also, just because exit() cleans up some standard system resources, does 
not mean it cleans up ALL resources. I do most of my programming with 
XNA, Direct3D, and the like. When you create objects that exist in 
graphics memory instead of RAM, you are responsible for managing that 
object. If I create a vertex buffer on the GPU, I am responsible for 
freeing that resource, not the "exit" function.

Teaching beginner programmers to call exit to leave the program is just 
simply a horrible decision. But hey, what do I know..

On 4/13/2011 7:41 PM, Sina Bahram wrote:
> I don't understand what that means.
>
> Totally destroys what structure?
>
> It's an exit ... of course it destroys everything.
>
> Furthermore, exit is an extremely clean way of exiting a program. It's a
million times better than return 0.
>
> It actually calls, in reverse order of course, all functions which
registered via atexit. It also closes streams, not only IO ones
> for that matter, and it gets rid of/cleans temporary files.
>
> Quite puzzled ...
>
> Take care,
> Sina
>
> -----Original Message-----
> From: programmingblind-bounce@xxxxxxxxxxxxx
[mailto:programmingblind-bounce@xxxxxxxxxxxxx] On Behalf Of Christopher
Coale
> Sent: Wednesday, April 13, 2011 9:38 PM
> To: programmingblind@xxxxxxxxxxxxx
> Subject: Re: again a newbee question
>
> Alright, I just wanted to force you to clarify, so you don't give Ashish
> the wrongi dea. ;) I grade C++ programming assignments, and I see new
> C++ programmers using the exit function simply because it's convenient,
> but it totally destroys the structure.
>
> On 4/13/2011 6:35 PM, Ken Perry wrote:
>> Well I was using exit as a concept more than a method since depending on
the
>> gui you code in there are things like finish, exit, delete and all kinds
of
>> way to make a program die.
>>
>> Ken
>>
>> -----Original Message-----
>> From: programmingblind-bounce@xxxxxxxxxxxxx
>> [mailto:programmingblind-bounce@xxxxxxxxxxxxx] On Behalf Of Christopher
>> Coale
>> Sent: Wednesday, April 13, 2011 9:28 PM
>> To: programmingblind@xxxxxxxxxxxxx
>> Subject: Re: again a newbee question
>>
>> Careful with saying "until you call exit." You don't want to give the
>> impression that the exit() function is okay in a structured program, do
>> we? ;)
>>
>> On 4/13/2011 6:25 PM, Ken Perry wrote:
>>> Nod you will not need things like scanf and getch and things of the like
>>> when you get into serious coding because you will be probably building
>>> windows apps of some kind and the window will remain open till you call
>>> exit.  This is just while you're learning so feel free to use scanf,
>> getch,
>>> getchar, or any of the things like read to just hold the program till
your
>>> ready to close.
>>>
>>> Ken
>>>
>>> -----Original Message-----
>>> From: programmingblind-bounce@xxxxxxxxxxxxx
>>> [mailto:programmingblind-bounce@xxxxxxxxxxxxx] On Behalf Of ashish
rohtagi
>>> Sent: Wednesday, April 13, 2011 9:05 PM
>>> To: programmingblind@xxxxxxxxxxxxx
>>> Subject: Re: again a newbee question
>>>
>>> sorry, I corrected the mistake about printf and scanf. thanks for the
>>> advice. take care, regards. ashish
>>>
>>> On 4/14/11, Littlefield, Tyler<tyler@xxxxxxxxxxxxx>    wrote:
>>>> I'm sorry, getch should be getchar. Also: it's fairly bad coding style
>>>> to put a printf on the same line as a scanf. Unless you have good
>>>> reason, try to keep your code separated. It makes it easier to read and
>>>> people don't miss things quite as easily.
>>>> On 4/13/2011 6:50 PM, ashish rohtagi wrote:
>>>>> like this?? #include<stdio.h>
>>>>>
>>>>> int main()
>>>>> {
>>>>> char me[20];
>>>>>
>>>>>
>>>>>
>>>>> printf("What is your name?"); scanf("%s",&me);
>>>>> printf("Darn glad to meet you, %s!\n",me);
>>>>>
>>>>> scanf("s%",&me);
>>>>>
>>>>> return(0);
>>>>> } but result is still the same. can I use getch fungtion? if yes
>>>>> please tell me how to use it . take care, regards.
>>>>>
>>>>>
>>>>> On 4/14/11, Jared Wright<wright.jaredm@xxxxxxxxx>     wrote:
>>>>>> It goes right between the last printf statement and the return
>>>>>> statement. It's job is to hold the program open at the end, so it
>> should
>>>>>> be the last statement before return, which ends the program.
>>>>>> On 4/13/2011 12:09 PM, ashish rohtagi wrote:
>>>>>>> hi Tyler, thanks for your suggestion, but I am unable to understand
>>>>>>> where to put second scanf. will you just once show me? take care,
>>>>>>> regards. ashish
>>>>>>>
>>>>>>> On 4/13/11, Littlefield, Tyler<tyler@xxxxxxxxxxxxx>      wrote:
>>>>>>>> Like ken said, use scanf to catch it before the window closes, or
run
>>>>>>>> it
>>>>>>>> in a command line. Here's what's happening:
>>>>>>>> You open the process, and the first scanf call blocks; that is to
>> say,
>>>>>>>> it will not process anything, it is simply waiting for the user to
>>>>>>>> input
>>>>>>>> something. But after it's done printing, there is no reason why it
>>>>>>>> should stay open because you don't tell it to. So run from the
>> command
>>>>>>>> prompt, use getch() to let you hit enter before it closes or use
>>>>>>>> another
>>>>>>>> scanf.
>>>>>>>> On 4/13/2011 9:32 AM, ashish rohtagi wrote:
>>>>>>>>> friends, thanks for all the  encouragement. here is my problem, I
>>> want
>>>>>>>>> to use scanf fungtion. in input and output but as soon as I give
my
>>>>>>>>> input and press enter the window disappears. it does not give
output
>>>>>>>>> based on my input. here is the code. #include<stdio.h>
>>>>>>>>>
>>>>>>>>> int main()
>>>>>>>>> {
>>>>>>>>> char me[20];
>>>>>>>>>
>>>>>>>>> printf("What is your name?"); scanf("%s",&me);
>>>>>>>>> printf("Glad to meet you, %s!\n",me); return(0);
>>>>>>>>> }
>>>>>>>>>
>>>>>>>>>
>>>>>>>>> On 4/13/11, Littlefield, Tyler<tyler@xxxxxxxxxxxxx>       wrote:
>>>>>>>>>> O. oops. In my defense, I haven't found coffee. :)
>>>>>>>>>> On 4/13/2011 7:46 AM, Jared Wright wrote:
>>>>>>>>>>> It's there, just on the same line as the printf statement.
>>>>>>>>>>> On 4/13/2011 9:35 AM, Littlefield, Tyler wrote:
>>>>>>>>>>>> good job on using int main, just don't forget a return 0; when
>> you
>>>>>>>>>>>> are
>>>>>>>>>>>> done. between the printf and the closing brace.
>>>>>>>>>>>> On 4/13/2011 6:36 AM, ashish rohtagi wrote:
>>>>>>>>>>>>> here is my code it compiles correctly but text just shows on
the
>>>>>>>>>>>>> screen for 1 second, I want it to stay. #include<stdio.h>
>>>>>>>>>>>>>
>>>>>>>>>>>>> int main()
>>>>>>>>>>>>> {
>>>>>>>>>>>>> printf("I will learn programming!\n"); return(0);
>>>>>>>>>>>>> }
>>>>>>>>>>>>>
>>>>>>>>>>>>>
>>>>>>>>>>>>> On 4/13/11, DaShiell, Jude T. CIV NAVAIR 1490, 1, 26
>>>>>>>>>>>>> <jude.dashiell@xxxxxxxx>       wrote:
>>>>>>>>>>>>>> You didn't put your printf statement in your message, but let
>> me
>>>>>>>>>>>>>> make a
>>>>>>>>>>>>>> guess. You didn't put a (\n) in before the closing quote mark
>> so
>>>>>>>>>>>>>> you
>>>>>>>>>>>>>> just put text on the screen without a line ending. That could
>> be
>>>>>>>>>>>>>> one
>>>>>>>>>>>>>> contributing factor. Another might be you didn't put an
>> #include
>>>>>>>>>>>>>> <stdio.h>       statement in at the top of your program and
maybe
>>>>>>>>>>>>>> used
>>>>>>>>>>>>>> #include<conio.h>. If that's the case, don't use printf with
>>>>>>>>>>>>>> conio.h
>>>>>>>>>>>>>> unless you also include stdio.h. For conio.h, cprintf is the
>>>>>>>>>>>>>> function
>>>>>>>>>>>>>> you want. Hope this helps.
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> -----Original Message-----
>>>>>>>>>>>>>> From: programmingblind-bounce@xxxxxxxxxxxxx
>>>>>>>>>>>>>> [mailto:programmingblind-bounce@xxxxxxxxxxxxx] On Behalf Of
>>>>>>>>>>>>>> ashish
>>>>>>>>>>>>>> rohtagi
>>>>>>>>>>>>>> Sent: Wednesday, April 13, 2011 8:04
>>>>>>>>>>>>>> To: programmingblind@xxxxxxxxxxxxx
>>>>>>>>>>>>>> Cc: punitdiwan@xxxxxxxxx
>>>>>>>>>>>>>> Subject: again a newbee question
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> friends, sorry here I am with another foolish question, sorry
>>> but
>>>>>>>>>>>>>> here
>>>>>>>>>>>>>> is no one to teach and I am learning myself. when I print any
>>>>>>>>>>>>>> text
>>>>>>>>>>>>>> on
>>>>>>>>>>>>>> screen using printf it quickly disappears. what should I do
>> that
>>>>>>>>>>>>>> it
>>>>>>>>>>>>>> should stay? take care, regards. ashish
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>>>>>>>>>> Thanks,
>>>>>>>>>> Ty
>>>>>>>>>>
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>>>> Thanks,
>>>> Ty
>>>>
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