Re: basic bash help

  • From: David Fitzjarrell <oratune@xxxxxxxxx>
  • To: Chris.Stephens@xxxxxxx, oracle-l@xxxxxxxxxxxxx
  • Date: Fri, 27 May 2011 11:51:52 -0700 (PDT)

Check the path for '.' as that allows running scripts/programs from the current 
directory, which is where you are when you run  the script.  If you remove that 
entry from the path then the 'proper' directory name should appear.
David Fitzjarrell

From: "Stephens, Chris" <Chris.Stephens@xxxxxxx>
To: "'oracle-l@xxxxxxxxxxxxx' (oracle-l@xxxxxxxxxxxxx)" <oracle-l@xxxxxxxxxxxxx>
Sent: Fri, May 27, 2011 11:42:28 AM
Subject: basic bash help

I’m writing a script to allow the sysadmin’s to kill any active sessions for a 
particular database user.  

If the script is called as root, I re-invoke it as oracle.  However, ‘dirname’ 
doesn’t seem to be working as expect and I have no idea why or how to get 
it.  A little bit of googl’ing didn’t help either so I turn to old faithful. J
export ORACLE_SID=xxxxxxx
export SCRIPT=`basename $0`
export SCRIPT_DIR=`dirname $0`
echo "${SCRIPT_DIR} is the script dir."
# Re-invoke this script as oracle if invoked as root
CUSER=`id |cut -d"(" -f2 | cut -d ")" -f1`
if [ "$CUSER" = "root" ]
        su - oracle -c "${SCRIPT_DIR}/${SCRIPT}"
        exit $?
<rest of script>
The script output is:
  “. is the script dir.”
The script is located in /home/oracle/scripts/sql/topsecret
Anybody know what the deal is?
I’m guessing it has something to do with sub-shells or something but I don’t 
know how to work around it.  I guess I can always hardcode the path but I would 
prefer not to.
Thanks for any help!
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