RE: SQL to retrieve all distinct records
- From: "Jocke Treugut" <treugut_tuning@xxxxxxxx>
- To: <oracle-l@xxxxxxxxxxxxx>
- Date: Thu, 15 Apr 2004 20:04:01 +0200
Hi, Alison!
I guess it depends on which row you want to show of all rows that have the
same A and B. Do you wanna show the one with first ROWID or ...???
Cheers / Jocke Treugut
www.treugut-tuning.com
-----Original Message-----
From: oracle-l-bounce@xxxxxxxxxxxxx
[mailto:oracle-l-bounce@xxxxxxxxxxxxx]On Behalf Of Alison Barak
Sent: den 15 april 2004 17:24
To: oracle-l@xxxxxxxxxxxxx
Subject: RE: SQL to retrieve all distinct records
I believe I have found a solution. Just wonder if anyone else has an
alternative or better approach?
select * from testing where rowid in (select min(rowid) from testing group
by a,b);
thanks.
alison
>From: "Alison Barak" <ambarak@xxxxxxxxxxx>
>To: oracle-l@xxxxxxxxxxxxx
>Subject: SQL to retrieve all distinct records
>Date: Thu, 15 Apr 2004 09:38:28 -0400
>
>Hi,
>can someone assist me with formulating a query to retrieve all distinct
>records. I need to retrieve all three columns a,b &c based on the distinct
>of the two columns a & b.
>
>SQL> select * from testing;
>A B C
>---------- ---------- ----------
>APPS APPS R1
>SYS SYS2 R2
>SYS SYS2 R3
>DOC DOC2 R4
>DC DC2 R5
>DOC DOC R6
>
>The result should be
>A B C
>---------- ---------- ----------
>APPS APPS R1
>SYS SYS2 R2
>DOC DOC2 R4
>DC DC2 R5
>DOC DOC R6
>
>
>I tried using group by/having count but was not successful. Any idea?
>
>Thanks.
>
>alison
>
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