Stupid arithmetic problem, but it does change the answer, at least in an emotional way. Here are the corrected numbers: Let's be really optimistic. Assume that the Arecibo dish, designed for 2.38 GHz, were scaled up in size to operate at, say, 600 MHz (UHF band). So that the gain in UHF remains 70 dBi. Then assume a state of the art TV receiver, capable of a sensitivity of -120 dBm (cryogenically cooled), for a 5.38 MHz bandwidth. Then assume, this being analog UHF, a transmitted power of 5 MW. And ignore absorption by the ionosphere (reasonably low in UHF). Okay, so the maximum allowable propagation loss, if transmitted power is 5 MW and receiver sensitivity is -120 dBm, is just under 217 dB. But our receive antenna has a supposed 70 dBi gain, so we should be able to tolerate a free space propagation loss of **287** dB. Assume the receiver is very advanced, capable of demod with 0 dB C/N ratio. So the total **287** dB loss can be used as free space distance only. Free space propagation loss is Loss = 32.45 + 20logbase10(freqMHz) + 20logbase10(distKm) Solve for distance, since you know the max loss allowable is **287** dB and the frequency is 600 MHz. Max distance = 8.9E+9 Km. Pluto is between 4.2E+9 Km and 7.5E+9 Km from Earth, which means that in principle, this signal could be receivable just within our solar system. As far as bouncing back to Earth, the highly reflective object would have be inside our solar system. Bert ---------------------------------------------------------------------- You can UNSUBSCRIBE from the OpenDTV list in two ways: - Using the UNSUBSCRIBE command in your user configuration settings at FreeLists.org - By sending a message to: opendtv-request@xxxxxxxxxxxxx with the word unsubscribe in the subject line.