[nanomsg] missing step in pubsub example
- From: "Jason E. Aten" <j.e.aten@xxxxxxxxx>
- To: nanomsg <nanomsg@xxxxxxxxxxxxx>
- Date: Sun, 14 Dec 2014 17:23:12 -0800
There is a step missing in the pub-sub example on the man page.
http://nanomsg.org/v0.5/nn_pubsub.7.html
How does the sub know to talk to the pub? There's never any connection made
between them, so the nn_recv just hangs forever.
Don't we need a bind and connect with an address in there somewhere?
Here is the example code from the man page.
int pub = nn_socket (AF_SP, NN_PUB);
int sub = nn_socket (AF_SP, NN_SUB);
int nbytes;
void *buf = NULL;
nn_setsockopt (sub, NN_SUB, NN_SUB_SUBSCRIBE, "foo", 3);
nn_setsockopt (sub, NN_SUB, NN_SUB_SUBSCRIBE, "bar", 3);
nbytes = nn_send (pub, "foo|Hello!", 10);
assert(nbytes == 10);
nbytes = nn_recv (sub, &buf, NN_MSG, 0); // hang here
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