[mso] Re: Access :VSMail mx3
- From: James LaBorde <jlaborde@xxxxxxxxx>
- To: "'mso@xxxxxxxxxxxxx'" <mso@xxxxxxxxxxxxx>
- Date: Fri, 19 Sep 2003 14:53:53 -0700
Glenda,
I think that your problem is that you appear to only be referencing the
table once rather than twice when you want to get the second set of data.
Try linking to a second instance of the table joining on fields that will be
the same. Try this out:
[mstFPlus].[Last], [mstFPlus].[first], [mstFPlus].[City], [mstFPlus].[state]
In(Select [mstFPlus].[L_Name] from [mstFPlus] join [mstFplus] as mstFPlus1
where [mstFPlus].[SCity] = [mstFPlus1].[SCity] and
[mstFPlus].[state]=[mstFPlus1].[state] and Left([mstFPlus].[f_name], 3) =
Left([mstFPlus1].[f_name],3) Having Count(*)>1)
I think this should probably do the trick.
James
-----Original Message-----
From: Glenda Wells [mailto:gwells@xxxxxxxxxxx]
Sent: Friday, September 19, 2003 2:10 PM
To: mso@xxxxxxxxxxxxx
Subject: [mso] Access :VSMail mx3
Hi All.
I'm trying to find duplicate information in an Access table using the
below in queries. I must have something wrong because in two of the
examples, Katie Lakerston and Katherine Lakerston should match, but it's
not happening.
Any advice appreciated. /g
Last, First, City & State
In (SELECT [L_NAME] FROM [mstFPlus] As Tmp GROUP BY
[L_NAME],[F_NAME],[SCITY],[STATE] HAVING Count(*)>1 And
LEFT([F_NAME],3) = LEFT([mstFPlus].[F_NAME],3) And [SCITY] =
[mstFPlus].[SCITY] And [STATE] = [mstFPlus].[STATE])
Last, First, Birth_DT & State
In (SELECT [L_NAME] FROM [mstFPlus] As Tmp GROUP BY
[L_NAME],[F_NAME],[BIRTH_DT],[STATE] HAVING Count(*)>1 And
LEFT([F_NAME],3) = LEFT([mstFPlus].[F_NAME],3) And
[BIRTH_DT]=[mstFPlus].[BIRTH_DT] And [STATE]=[mstFPlus].[STATE])
Last, First & Zip
In (SELECT [L_NAME] FROM [mstFPlus] As Tmp GROUP BY
[L_NAME],[F_NAME],[SZIP_CODE] HAVING Count(*)>1 And LEFT([F_NAME],3) =
LEFT([mstFPlus].[F_NAME],3) And LEFT([SZIP_CODE],5) =
LEFT([mstFPlus].[SZIP_CODE],5))
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