[mso] Re: Access ???
- From: Glenda Wells <gwells@xxxxxxxxxxx>
- To: "'mso@xxxxxxxxxxxxx'" <mso@xxxxxxxxxxxxx>
- Date: Tue, 25 Jun 2002 14:51:26 -0400
Waaahhh, ha, hic, sob...my way isn't best...barely better than doing it by
hand. I'm soooo frustrated! All this terrific technology in front of me
and I haven't a clue how to take advantage of it. Well, actually, I do have
a clue, two even, which I got from this list so please, don't any of y'all
give up on me. I'm learning, rather like the first parasite dragging itself
out of the primordial ooze but still, it's progress. /gl
-----Original Message-----
From: Colli, Anthony G [mailto:Anthony.Colli@xxxxxxx]
Sent: Tuesday, June 25, 2002 2:43 PM
To: 'mso@xxxxxxxxxxxxx'
Subject: [mso] Re: Access ???
Glenda-
I just spent a few minutes trying to get a crosstab to work too. I didn't
have much luck either. Maybe your way is the best way. The northwind
database has a pretty good example of a crosstab query, check it out. MS
Access uses JET as a database, and it is not ANSI compliant. If it were you
could write your own crosstab query using SELECT CASE statements in the sql.
-Anthony
-----Original Message-----
From: Glenda Wells [mailto:gwells@xxxxxxxxxxx]
Sent: Tuesday, June 25, 2002 1:40 PM
To: 'mso@xxxxxxxxxxxxx'
Subject: [mso] Re: Access ???
I know I'm missing a step somewhere but...
I tried doing a Pivot Table in Excel and that didn't work.
Here's a sample of what I started with. 3 ID for BEST OOO3, 2 ID for BEST
0004 and 1 ID for CARS 2000.
ID Bldg Room Assignment Number
757 BEST 0003 BEST 0003 1
6760 BEST 0003 BEST 0003 1
2356 BEST 0003 BEST 0003 1
4448 BEST 0004 BEST 0004 1
9922 BEST 0004 BEST 0004 1
7017 CARS 2000 CARS 2000 1
This is the result I need
Assignment Roomie1 Roomie2 Roomie3
BEST 0003 757 6760 2356
BEST 0004 448 9922
CARS 2000 7017
When I tried an Access Crosstab query just now, with Assignment as Row
Heading and ID as Column, got error too many crosstab column headers.
There's 762 assignments and 1,391 ID
-----Original Message-----
From: Colli, Anthony G [mailto:Anthony.Colli@xxxxxxx]
Sent: Tuesday, June 25, 2002 1:21 PM
To: 'mso@xxxxxxxxxxxxx'
Subject: [mso] Re: Access ???
Glenda-
Now I understand perfectly. A Crosstab query is what you are looking for.
It's like a pivot table in Excel.
-Anthony
-----Original Message-----
From: Glenda Wells [mailto:gwells@xxxxxxxxxxx]
Sent: Tuesday, June 25, 2002 1:16 PM
To: 'mso@xxxxxxxxxxxxx'
Subject: [mso] Re: Access ???
Just in case anyone is interested, here's an example of the result.
Assignment is a concatenate of Building and Room. Roomie 1 is FIRST and
Roomie2 is LAST in the aggregate query below where I ended up with 625
records with 2 unique ID per Assignment.
Assignment Roomie1 Roomie2
BEST 0001 16 207
BEST 0004 448 922
CARSON 3101 617 544
CARSON 3102 2813 5796
SELECT tblRoomAssignmentByPIDM.Assignment,
First(tblRoomAssignmentByPIDM_1.SLRRASG_PIDM) AS Roomie1,
Last(tblRoomAssignmentByPIDM_1.SLRRASG_PIDM) AS Roomie2 INTO tblRoomie1 FROM
tblRoomAssignmentByPIDM INNER JOIN tblRoomAssignmentByPIDM AS
tblRoomAssignmentByPIDM_1 ON tblRoomAssignmentByPIDM.SLRRASG_PIDM =
tblRoomAssignmentByPIDM_1.SLRRASG_PIDM
GROUP BY tblRoomAssignmentByPIDM.Assignment
HAVING (((Count(tblRoomAssignmentByPIDM.Number))=2))
ORDER BY tblRoomAssignmentByPIDM.Assignment;
Hi All.
Our email system was out of commission for a while so just getting back and
want to catch up on my roommate table problem.
I have 1,391 persons assigned to 762 rooms: 135 Singles, 625 Doubles, 2
Triples.
The original list consists of the person ID, the building code and the room
number.
What I did was this for the double rooms, twice. The result is 2 temporary
tables with 625 records each.
SELECT tblRoomAssignmentByPIDM.Assignment,
First(tblRoomAssignmentByPIDM_1.SLRRASG_PIDM) AS Roomie1,
Last(tblRoomAssignmentByPIDM_1.SLRRASG_PIDM) AS Roomie2 INTO tblRoomie1 FROM
tblRoomAssignmentByPIDM INNER JOIN tblRoomAssignmentByPIDM AS
tblRoomAssignmentByPIDM_1 ON tblRoomAssignmentByPIDM.SLRRASG_PIDM =
tblRoomAssignmentByPIDM_1.SLRRASG_PIDM
GROUP BY tblRoomAssignmentByPIDM.Assignment
HAVING (((Count(tblRoomAssignmentByPIDM.Number))=2))
ORDER BY tblRoomAssignmentByPIDM.Assignment;
I appended the result of the 2 queries to a table structure that gives
Roomie1 and Roomie2 ID's the title of Main which is then linked via quires
by the ID's to other tables for name and address information.
Kludgy but it works. But there has to be a programmatic was to accomplish
the task and include the singles and triples as well.
The single rooms are simple, and the 2 triples, I'll do by hand.
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