[mso] Re: Access ???

  • From: Glenda Wells <gwells@xxxxxxxxxxx>
  • To: "'mso@xxxxxxxxxxxxx'" <mso@xxxxxxxxxxxxx>
  • Date: Tue, 25 Jun 2002 13:09:07 -0400

Hi Ken.

Thanks. I concatenated Building and Room for a unique record and the Person
ID is already unique.  I then used Anthony's suggestion to get a number of
occupants per room.  If you're interested, I sent an earlier email with a
bit more detail about what I did.  I'm not happy with the process but the
result works.

-----Original Message-----
From: Ken Grubb [mailto:KGRUBB@xxxxxxxxxxxx] 
Sent: Monday, June 24, 2002 10:07 PM
To: mso@xxxxxxxxxxxxx
Subject: [mso] Re: Access ???



Glenda,

I'm a little confused.  Most logical course is to make one table for Rooms
and another table for Assignments.
- Primary Key on your Rooms table should be the room number as that would
most likely be unique.
- Primary Key on the Assignments table can be whatever you like, even an
AutoNumber, just so long as it's unique and it refers to the Occupant.
- The Room Assignment field in your Assignments table should be a foreign
key to the Rooms table.  This way you'll only ever have valid room
assignments.  After all, the room must REALLY exist for it to be assigned.
- Finally, use Anthony's suggestion in a Query to determine how many folks
are in each room.  As he suggested, you can turn your Select Query into a
Make Table Query and you'll have a table showing how many people are in each
room.

If I haven't completely perplexed you, this should keep you busy.

HTH,

Ken Grubb
Burlington, NC


> -----Original Message-----
> From: Glenda Wells
> Sent: Monday, June 24, 2002 16:40
> Subject: [mso] Re: Access ???
>
>
> I  have no idea what you're talking about Anthony.


> -----Original Message-----
> From: Colli, Anthony G
> Sent: Monday, June 24, 2002 2:14 PM
> Subject: [mso] Re: Access ???
>
>
> Do a count of Assignment >=2 in your case it might be something like
>
> SELECT Assignment, COUNT(Assignment) FROM MyTable
> HAVING Count(Assignment) >=2
>
> You can make a table from that query and then use it on the one side 
> of a one -> many relationship.


> -----Original Message-----
> From: Glenda Wells
> Sent: Monday, June 24, 2002 1:27 PM
> Subject: [mso] Access ???
>
>
> I have a list of people in rooms.  1, 2 or 3 persons
> per room.  If more than one person, then the persons
> are roommates. How can I tell Access in a query that
> if there are 2 or more ID's in 1 room, that they are
> the roommates. My objective is to send a letter to
> these people telling them that the other person or
> persons in the room are his/her roomie.
>
> Here's what I have
> Query2
> Assignment ID
> RADM 0001      16
> RADM 0002      95
> RADM 0002      792
> RADM 0002      758
> RADM 0003      23
> RADM 0003      247
> RADM 0004      448
> RADM 0004      5292


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