#### Answer

$x=1005$

#### Work Step by Step

As we know: $logm-log n=log\dfrac{m}{n}$
Thus, $log(\dfrac{x^2-25}{x+5})=3$
or, $log(\dfrac{x^2-25}{x+5})=3$
or, $log(x-5)=3$
or, $x-5=10^3 \implies x-5=1000$
or, $x=1005$

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Published by
Pearson

ISBN 10:
0-13417-894-7

ISBN 13:
978-0-13417-894-3

$x=1005$

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