"Could you fill this out a bit? There's some relation (don't ask me to say exactly what it is) between knowledge and certainty; but it doesn't follow from someone's being absolutely certain that x, that x." Hear, Hear. (for Xmas comes but once a year!) --- I take R. Paul's point as correct. Since the Thaetetus of Plato, there is some agreement that Donal knows 2 + 2 = 5 =df (i) Donal believes/imagines 2 + 2 = 5 (ii) Donal has a way of proving that 2 + 2 = 5 [causal link, conclusive evidence] (iii) 2 + 2 = 5 I agree with Popper, Donal, and Andreas, that (iii) belongs in the ONTOLOGICAL level -- and it's the realm of Truth, so-called (but this is in itself controversial, for surely we want 'truth' to be a _relation_, not just an ontological _datum_. In (i) I am taking 'imagine' and 'think' as interdefinable. I realise P. Stone's point about the etymological connection with _imago_, and I'll work on it. But then, if you think of 'see', you cannot either say, "I saw a rainbow" if there was no rainbow to be _seen_ -- and either you *disimplicate* [good technical use here] the 'implication' (not implicature) standardly associated with 'see' -- and start, to use Grice's phrase, to 'speak loosely'. Them the link (ii) is between the ultimately ONTOLOGICAL Iiii) and (i) the primarily DOXASTIC (I would not use 'epistemological', as it begs the question that this _is_ episteme, which the Greeks reserved for 'knowledge', rather than 'doxa', or mere belief/opinion/imaginings. I'll re-read Donal's interesting post about Popper to see if I get a clearer picture of his thing (Donal says other -- than Donal -- thought like that, too). I agree with P. Stone that A. Palma is _over-imagining_ things. And, I wonder what version of "1984" was broadcast yesterday, and why it reverberates. I suppose it's the idea of a Government guiding us to believe _false_ things? Cheers, JL Buenos Aires, Argentina **************************************Check out AOL's list of 2007's hottest products. (http://money.aol.com/special/hot-products-2007?NCID=aoltop00030000000001)