Re: Licensing
- From: "Thor" <thor@xxxxxxxxxxxxxxx>
- To: "[ISAserver.org Discussion List]" <isalist@xxxxxxxxxxxxx>
- Date: Mon, 3 Nov 2003 12:04:11 -0800
By the way- I agree with your weekend rant.
This one's for you, baby.
http://www.securityfocus.com/columnists/195
----- Original Message -----
From: "John Tolmachoff (Lists)" <johnlist@xxxxxxxxxxxxxxxxxxx>
To: "[ISAserver.org Discussion List]" <isalist@xxxxxxxxxxxxx>
Sent: Monday, November 03, 2003 10:57 AM
Subject: [isalist] Re: Licensing
http://www.ISAserver.org
If the server is a member of a domain, it follows the licensing for the
domain.
What exactly are you trying to figure out?
If you have one hundred local users, and you have the appropriate CALs for
the domain, and you have the appropriate license for the server OS and ISA,
then those one hundred users are fully licensed to use ISA.
John Tolmachoff
Engineer/Consultant/Owner
eServices For You
> -----Original Message-----
> From: William Rascher [mailto:wrascher@xxxxxxxxxxxxxxxx]
> Sent: Monday, November 03, 2003 10:45 AM
> To: [ISAserver.org Discussion List]
> Subject: [isalist] Re: Licensing
>
> http://www.ISAserver.org
>
> What about the server OS that ISA is running on?
>
> William
>
> -----Original Message-----
> From: Jim Harrison [mailto:jim@xxxxxxxxxxxx]
> Sent: Friday, October 31, 2003 16:29
> To: [ISAserver.org Discussion List]
> Subject: [isalist] Re: Licensing
>
>
> http://www.ISAserver.org
>
> There's no such thing as per-connection licensing for ISA.
>
> Jim Harrison
> MCP(NT4, W2K), A+, Network+, PCG http://www.microsoft.com/isaserver
> http://isaserver.org/Jim_Harrison
> http://isatools.org
>
> Read the help, books and articles!
> ----- Original Message -----
> From: "Rascher William" <wrascher@xxxxxxxxxxxxxxxx>
> To: "[ISAserver.org Discussion List]" <isalist@xxxxxxxxxxxxx>
> Sent: Friday, October 31, 2003 13:49
> Subject: [isalist] Licensing
>
>
> http://www.ISAserver.org
>
> Does anyone know what happens with ISA (and any http connections) when the
> concurrent licensed connections is exceeded? Are connections Q'ed?
>
> William
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