Scott, Your picture is incorrect: 1 --- Network --- 3 | | 2 It is really Tx_Pad --- Network --- Rx_Pad --- Input_to_Equalization --- Output_of_Equalization There is a high impedance connection between ports Rx_Pad and Input_to_Equalization. This should answer your question. Walter Walter Katz 303.449-2308 Mobile 720.333-1107 wkatz@xxxxxxxxxx www.sisoft.com -----Original Message----- From: ibis-macro-bounce@xxxxxxxxxxxxx [mailto:ibis-macro-bounce@xxxxxxxxxxxxx]On Behalf Of Scott McMorrow Sent: Thursday, May 27, 2010 6:04 PM To: IBIS-ATM Subject: [ibis-macro] another silly IBIS-AMI question about deriving the impulse response of a channel Since the analog channel is required to be LTI from driver to receiver, I believe that in order to create a correct impulse response it is necessary to know what the termination impedance should be. In the case where a driver or a receiver is terminated at the end of the line, the termination impedance is obvious. So, for a 100 ohm differential system the differential impedance used for impulse response extraction is 100 ohms. Essentially the high-impedance receiver amplifier, or driver current sources are considered to be lumped at the termination network. How are people modeling, extracting, and simulating drivers and receivers where the high-impedance ports are physically isolated from the termination, where the waveform in the algorithmic domain (driver/receiver) is substantially different than the waveform in the analog domain at the termination? I'm confused, since IBIS-AMI does not include the on-die termination network, except in the rudimentary and unsatisfying form of a *.ibs model, and that model is a lumped approximation. In my mind, in order to correctly extract an impulse response of a channel that will give a correct representation of the waveform at the receiver, one has to either perform a transient simulation of the full circuit from the driver to the receiver, or perform frequency domain modeling to impulse response transformations with known driver/receiver input impedance. Otherwise, the resulting impulse response is wrong. For a hypothetical 50 ohm single-ended transmitter or receiver, the simplest circuit that can correctly model many transmitters and receivers is the following network: 1 --- Network --- 3 | | 2 where: Port 1 = 50 ohm Port 3 = 50 ohm Port 2 = some high impedance. and Port 1 to Port 2 is the path used for computation of the impulse response If the Network is lumped into: 1 --- Network --- 2 The resulting impulse response and waveform is different. How are people solving this problem? regards, Scott -- Scott McMorrow Teraspeed Consulting Group LLC 121 North River Drive Narragansett, RI 02882 (401) 284-1827 Business (401) 284-1840 Fax http://www.teraspeed.com Teraspeed® is the registered service mark of Teraspeed Consulting Group LLC