Does anybody on the list think the jitter (A) should be injected at the input of the TX output stage (OUT), as drawn? I'm trying to figure out if I wrote this down wrong or if there is still some disagreement among the committee members. Greg (See attached file: Serdes_Jitter_Model_092011.ppt) Greg Edlund Senior Engineer Signal Integrity and System Timing IBM Systems & Technology Group 3605 Hwy. 52 N Bldg 050-3 Rochester, MN 55901 From: "Walter Katz" <wkatz@xxxxxxxxxx> To: Gregory R Edlund/Rochester/IBM@IBMUS, <ibis-macro@xxxxxxxxxxxxx> Date: 09/21/2011 06:11 PM Subject: RE: [ibis-macro] Jitter Model Discussion Greg, I believe that (A) should be at the input to the EQ of the Tx Block since it is applied to the stimulus input to the Tx algorithmic model. Walter From: ibis-macro-bounce@xxxxxxxxxxxxx [ mailto:ibis-macro-bounce@xxxxxxxxxxxxx] On Behalf Of Gregory R Edlund Sent: Wednesday, September 21, 2011 6:39 PM To: ibis-macro@xxxxxxxxxxxxx Subject: [ibis-macro] Jitter Model Discussion I modified the drawings as we were talking yesterday. Let me know if I missed something or misinterpreted someone's statement. As I understood the conversation, some things are still under discussion: 1. Where does RX_Sj get injected (Kumar's point)? 2. Is a TX termination block really necessary? I suggest we spend one more session listing the physical origin(s) for each type of jitter on the first slide. It would be great to have a circuit designer on hand for this! In the future, I would be glad to function as the scribe by making updates to the charts as the new spec evolves. (See attached file: Serdes_Jitter_Model_092011.ppt) Greg Edlund Senior Engineer Signal Integrity and System Timing IBM Systems & Technology Group 3605 Hwy. 52 N Bldg 050-3 Rochester, MN 55901