Hey Stefano,
ref = sDec; means you assign value of sDec to the reference of ref, in your case sInc. a reference relationship can only be established once.
sDec is never changed, hence its zero value sInc is assigned to zero value, and decremented each time.
Bye, Jérôme
Stefano Ceccherini a écrit :
I found a weird behaviour of gcc. I don't know if it's normal, and I'd like someone more "in the know" than me to explain :)
This code:
#include <stdio.h>
static int sInc = 0; static int sDec = 0; static int sCounter = 0;
static void do_stuff() { int &ref = sInc; ref++; ref = sDec; ref--; sCounter++; printf("inc: %d (should be %d), dec: %d (should be %d)\n", sInc, sCounter, sDec, -sCounter); }
int main() { for (int i = 0; i < 10; i++) do_stuff(); }
Results in this printout: inc: -1 (should be 1), dec: 0 (should be -1) inc: -1 (should be 2), dec: 0 (should be -2) inc: -1 (should be 3), dec: 0 (should be -3) inc: -1 (should be 4), dec: 0 (should be -4) inc: -1 (should be 5), dec: 0 (should be -5) inc: -1 (should be 6), dec: 0 (should be -6) inc: -1 (should be 7), dec: 0 (should be -7) inc: -1 (should be 8), dec: 0 (should be -8) inc: -1 (should be 9), dec: 0 (should be -9) inc: -1 (should be 10), dec: 0 (should be -10)
Am I dumb if I think it should be different or it's a bug in our gcc ?