[openbeos] Re: Icon Contest Results Math
- From: "Meanwhile -" <meanwhile@xxxxxxxxxx>
- To: openbeos@xxxxxxxxxxxxx
- Date: Mon, 04 Sep 2006 17:28:53 +0800
Hello Petter,
Hmm, the default choice should have been: -- (a.k.a. a blank vote, meaning:
abstain from voting).
My conclusion is :if this option isn't given, there's no way of calculating an
overall average per set.
I hope I am wrong but I came to this after first trying to find a way of
spreading the differences between average
one and average two, taking into account the total number of statements, the
total number of voters and the
average between highest possible score a single voter can give and lowest
possible score a single voter can give.
But to calculate this 'lowest possible score a single voter can give', you'd
need to be able to say which lowest value
(0) the voter gave for a statement was deliberately chosen and which wasn't.
As the default is 0 now, that's impossible.
Again: I really hope I am wrong, but I'm willing to risc ridicule because in
case the election had to be started over,
it's: the sooner the better.
Hoping for more reactions from others,
Meanwhile
> ----- Original Message -----
> From: "Petter Holt Juliussen" <post@xxxxxxxxxxxx>
> To: openbeos@xxxxxxxxxxxxx
> Subject: [openbeos] Re: Icon Contest Results Math
> Date: Mon, 04 Sep 2006 09:00:31 +0200
>
>
> Petter Holt Juliussen wrote:
> > Hi,
> >
> > I'm working on the results page now and I am wondering if I
> > should count "not voted" as 0, or should I try to skip those?
> Another example to clearify:
>
> - 3 sets
> - 4 voters
> - To make it simpler; there are only 1 statement per set.
>
> Set 1:
> Voters: 3 of the 4
> Vote sum: 3 + 2 + 4 = 9
> Average one: 9 divided on 3 voters = 9 / 3 = 3
> Average two: 9 divided on 4 voters = 9 / 4 = 2,3
>
> Set 2:
> Voters: 1 of the 4
> Vote sum: 3 = 3
> Average one: 3 divided on 1 voters = 3 / 1 = 3
> Average two: 3 divided on 4 voters = 3 / 4 = 0,8
>
> Set 3:
> Voters: 0 of the 4
> Vote sum: 0
> Average one: 0 divided on 0 voters = 0 / 0 = --
> Average two: 0 divided on 4 voters = 0 / 4 = 0
>
>
> Should we go for average one, or average two? As you can see, the
> results differ a lot. If we go for average one, you can see
> that Set 1 and Set 2 have the same average and are ranked the same
> although only 1 did vote on Set 2 opposed to 3 on Set 1.
>
> This boils down to: Should those who don't vote on a set at all
> count as vote 0 in th overall average?
>
>
> Petter
>
--
__________________________________________________
Now you can search for products and services
http://search.mail.com
Powered by Outblaze
Other related posts:
