Am 30/04/2017 um 08:55 schrieb Ingo Weinhold:
I'm not familiar with the code in question, but generally, if you haveDo you really have to do that? Can't you simply delete the lockUnless I really missed something, the lock is the looper lock for the
instead? That would be a good way to let lockers fail immediately.
BPoseView, and this code will deadlock in the destructor unless there is
a mechanism for it to timeout. So, no, that's not an option.
code paths with inverse locking order, the solution should be to fix
that, not to work around with timeouts.