[geocentrism] Re: acceleration calcs

  • From: allendaves@xxxxxxxxxxxxxx
  • To: geocentrism@xxxxxxxxxxxxx
  • Date: Mon, 28 Jan 2008 13:53:16 -0800 (PST)

We cannot measure translations with a gyroscope, whether accelerated or not."  
Regner.  

Yes, but then why would you want to attempt to measure that aspect of earth's 
supposed orbital motion anyway?  We are only looking for changes in 
acceleration not absolute values of velocity ?????...The question before us is 
can we detect absolute velocity... not invoke as proof for something the very 
thing that is in question!? ......As a side issue on the other hand as it would 
relate to gyroscopic motions, the earth also supposedly spin's......we can 
measure gyroscopic motions of free falling objects within earths inertial 
gravitational field and the earth is in the sun's presumably free 
falling....... attempts were made to measure that....guess what ..they can and 
do measure a motion equivilent to earth's sidreal period (daily) but detected 
absolutly none for it's annual!......ummmmmmmmmm

To summarize:
* You cannot measure absolute velocity
   - or more importantly it doesn't matter to physics.

That is incorrect, it is only not important to GR's version of physics but that 
is what is in question....? That statement is only true if you assume GR is 
true first but when you do that then you cannot ever claim to be able to 
falsify the very thing you use to interpret the data with!?

The problem is with inertial reference frames the fact that HC has the earth in 
a translational orbit is irrelevant for what is in question in this discussion. 
 You can measure absolute acceleration.

That is all we would want to measure the annual changes............. but that 
has failed at every attempt in science even though the sidereal period has been 
consistently detectable for the last 100+ years...ummmmm

This is in part the importaince of the questions 

1. can absolute velocity be measured? how do we know?..by vertue of a very 
theory that we must use in order to make such a determintion? That is not 
validating the tehory that is using the theory to determine the conclusion!?
2. is grav and inertia the same? how do we know?

You cant envoke the very theory that claims to be falsifiable as proof  for 
it's own conclusions or the beachmark for evaluating/ interpriting the data 
in.....!? 
My aggression is not to GR my aggresion is the method of its application/ 
evaluation.

Our proof is both direct and indirect we identify the two basic posibilities 
absolute motion v not absolute motion and eliminate the looser but we cannot 
use the conclusions of one theory to base the data interpritaions on.  we do 
have to accept the observations at face value untill such time as they are 
shown external of a circular falicy that they are something else.


----- Original Message ----
From: philip madsen <pma15027@xxxxxxxxxxxxxx>
To: geocentrism@xxxxxxxxxxxxx
Sent: Monday, January 28, 2008 1:30:09 PM
Subject: [geocentrism] Re: acceleration calcs


"We cannot measure translations with a gyroscope, whether accelerated or not."  
Regner.  
 
Of course!  I should be ashamed for not applying what I knew from experience, 
and my recent grasp of the term translation. 
 
In a two body system excluding all other reference points,  there seems to be 
know way of feeling "detecting" which body is moving around which except by the 
logic of known physics as regards the influence of gravity and centrepetal 
force. Experimental proof would need to be obtained of the relative masses of 
the bodies, which of course has been done betwen the sun and the earth. There 
is no way anyone can claim the sun is some light airy gas ball. 
 
Thanks Regner. 
 
Philip.  


----- Original Message ----- 
From: Regner Trampedach 
To: geocentrism@xxxxxxxxxxxxx 
Sent: Monday, January 28, 2008 4:25 PM
Subject: [geocentrism] Re: acceleration calcs


Regner's reply to Philip's in blue...

philip madsen wrote: 
Regner said. 
"Eh, no!
We can still measure our position/velocity relative to the stars.
Then it is a matter of conviction, I guess, whether you believe the whole 
Universe
to be moving that way, or just the Earth." 
 
Regner my words were not phrased too well. What I meant by certainty was that 
there is no absolute way of knowing or finding a spot with absolutely NO 
MOTION. You can relate movement between the stars, and the earth. but motion 
(constant velocity no acceleration ) as such in isolated space cannot be 
detected. 
 
To summarize:
* You cannot measure absolute velocity
   - or more importantly it doesn't matter to physics.
* You can measure absolute acceleration.

You also responded with, "Eh, they do.
You don't need more than that - you just integrate once over time to get 
velocity, and
twice to get position. [ I do not follow. What device can detect motion 
movement and velocity, except with respect to other bodies, such as the stars, 
whose own movements as a whole, can only be assumed. ] 

If you get your velocities from integration over acceleration, there is still 
an integration
constant which is undetermined - which means you still don't have an absolute 
velocity.


But they won't detect acceleration of an object free-falling in a gravitational 
field.
We both argued for that..." [ yes, and therefore I have confused myself. I had 
always assumed that a gyroscope in a satellite would show the curved motion . 
Just as I expect one to show the fall of the earth around the sun????
Could you please explain this for us. 
A gyroscope keeps it's orientation in space - therefore we can measure 
rotations.
We cannot measure translations with a gyroscope, whether accelerated or not.
...Unless, of course, you use the gyroscope in a manner akin to this:
How to measure the height of a building using a barometer

     Regner

 
Philip. 
 
 


 
Philip. 


----- Original Message ----- 
From: Regner Trampedach 
To: geocentrism@xxxxxxxxxxxxx 
Sent: Thursday, January 24, 2008 1:08 PM
Subject: [geocentrism] Re: acceleration calcs


philip madsen wrote: 
The truck drives along a turn in the road.
* A ball is dropped from the ceiling of the container.

Thanks Regner.. I now glean what is meant by the "fiction".. Actually we had 
discussed the falling ball in a transparant railway carriage passing a station 
a few times here on this list. I just missed the connection as regards the 
"fiction" of observation. 
 
I am glad that clarified it.

You make a good case for it being impossible for anybody to establish absolute 
certainty for any position or movement in space. (we've been here before as 
well) 
 
Eh, no!
We can still measure our position/velocity relative to the stars.
Then it is a matter of conviction, I guess, whether you believe the whole 
Universe
to be moving that way, or just the Earth.
But apart from that, you are right that there is no "absolute certainty" in the 
world
of science.

Its claimed inertial devices will detect acceleration. but that is only part of 
motion...
Eh, they do.
You don't need more than that - you just integrate once over time to get 
velocity, and
twice to get position.
But they won't detect acceleration of an object free-falling in a gravitational 
field.
We both argued for that...

        Regner


Philip. 
----- Original Message ----- 
From: Regner Trampedach 
To: geocentrism@xxxxxxxxxxxxx 
Sent: Wednesday, January 23, 2008 1:10 PM
Subject: [geocentrism] Re: acceleration calcs


Exactly, Philip.
The Earth, and we with it, are in free fall around the Sun, with the 
gravitational acceleration
by the Sun (and towards the Sun) keeping us in our elliptic orbit.
   Without careful analysis, I actually thought that you might be able to 
detect it, but you
are right, Philip. This is also stated in Einsteins equivalence principle which 
states that
a free-falling reference frame is an inertial reference frame, and there will 
therefore be no
fictitious forces (centrifugal-, Coriolis- and Euler-forces). The equivalence 
principle
means that the orbit of Earth can just as well be seen as the Earth traveling 
along a straight
line in a curved space - the two are equivalent - and the latter is described 
by general relativity.

   As a partial reply to your (much) earlier post on pseudo forces, I will note 
a few facts
on them here - and there is nothing dubious about them.
   Pseudo forces, more often called fictitious forces, arise when your 
reference frame is
being accelerated. Let's say you set up a laboratory inside a container on a 
trailer truck.
* The truck drives along a turn in the road.
* A ball is dropped from the ceiling of the container.
Imagine the container turning transparent, so that your colleague can record the
trajectory of the ball, as seen from the roadside
* your colleague will see the ball follow a parabola determined by the speed of
   the truck when the ball was released, and the local acceleration of gravity.
   Only one force, gravity, acts on the ball:  F_obs = F_grav.
* You, however, will see the ball being acted upon by another force, since the
   ball (and you...) will be accelerated towards the side of the container:
                  F_obs = F_grav + F_fict
   This force is entirely due to the truck accelerating iin the opposite 
direction,
towards the inside of the bend in the road, and we call it a fictive force.
Fictive forces are trivial (but often cumbersome) to derive as the opposite of
the acceleration of your (non-interial) reference frame.

          Regards,

              Regner


philip madsen wrote: 
re Alan and Regners figures.  
 
 
On this business of "feeling" acceleration, whilst I do not pretend to having 
had enough interest in checking the figures, I still reason that its a matter 
of how forces are applied, as to whether you feel anything. 
 
In a suddenly braking car you get flung forward...  because the force is at the 
wheels..  But if the breaking force was applied to every molecule of the 
vehicle including you, then I concieve no effect to be "felt" 
 
If I take the orbiting space station as an example, the people inside and even 
ouside are all exposed to the same accelerating forces.. They follow the orbit 
of the vehicle..  when the man steps outside, he does not get flung off on a 
merry plunge towards the sun or the earth for that matter. He would not "feel" 
any movement. Yet he is circling the earth every few hours. Thats travelling a 
fast corner. 
 
Philip. 
----- Original Message ----- 
From: Regner Trampedach 
To: geocentrism@xxxxxxxxxxxxx 
Sent: Tuesday, January 22, 2008 4:59 PM
Subject: [geocentrism] Re: acceleration calcs


Alan, 
 Thanks for your calculation, but I'm afraid you made a mistake - it's easy to 
do with all those 
crazy units Americans juggle with. You forget that your velocities are still 
per hour, while
you have the change of velocity per second, so your result is actually: 
(1)               11.43 cm/(hour*s) = 0.003175 cm/s2    (cm per second squared) 
 The actual change is: 
(2)               (30.29e5 cm/s - 29.29e5 cm/s) / (year/2d0)  = 0.006338 cm/s2 
We agree on the velocities and the difference in velocity - I just use 
centimeter-gram-second (cgs) 
units. One year is 365.26 days * 24 hours/day * 3600 s/hour = 3.155693e7 s. 
The change happens during half a year (I divide year by 2, in Eq. [2]) so you 
would actually 
have underestimated the change (as you can see from my correction, Eq. [1]). 
  It is always a good idea to put your result in perspective by comparing with 
another relevant 
quantity - the gravitational acceleration at the surface of Earth is about 
g=9.8 m/s2 on average, 
which means that the acceleration along Earth's orbit is 
(3)               (0.006338 cm/s2) / (980 cm/s2) = 0.000006467 
times the average gravitational acceleration at the surface of Earth, g.
or conversely, the acceleration along Earth's orbit is 154600 times smaller 
than g.  I don't 
think you would notice that! 

  But that is obviously a tiny component of the accelerations actually involved.
Remember that (in HC) the direction of the velocity has also changed over the 6 
months 
and the velocities in the two instances will be exactly opposite. We can get a 
rough estimate 
of that acceleration by just adding the two velocities in Eq. (2), since  
a-(-b) = a+b, to get: 
(4)               (30.29e5 cm/s + 29.29e5 cm/s) / (year/2d0)  =  0.3776 cm/s2 
which is then 2595 times smaller than g. Absolutely measurable, but it wouldn't 
exactly 
knock you over. 

       Regner 


allendaves@xxxxxxxxxxxxxx wrote: 
Try to move 4.5 inches within one sec without feeling/ (being abel to detect 
that using current technology) it. This demonstrates the crux of the problem 
with earths inertial motion. Appealing to some imaginary reason why you could 
not detect it in the earth but you could  with anything and everything else is 
not going to work untill you can first prove that your imaginary reason exist 
in reality. NO one isarguing it could be, but if we are to arive at a 
conclusion and proclaim it logical we have to prove the variables along the way 
not make them up as we go along. that is the fundimental difference between GC 
& HC. GC accepts as proof only the effidence presented as it goes along through 
the discovery process.....HC makes it up as it goes along to save it's 
conclusions.....
 

 
----- Original Message ----
From: Allen Daves <allendaves@xxxxxxxxxxxxxx>
To: geocentrism@xxxxxxxxxxxxx
Sent: Monday, January 21, 2008 8:38:51 AM
Subject: [geocentrism] Re: acceleration calcs


 
Here it is ..quick & rough....
 
18.5 miles per second average speed * 60 sec for min * 60 min for MPH = 
66600MPH or 
The ~ avg change over the course of a year is 3.4%* 66600= 2264.4     / 365.4 
days=6.2038 MPH per day /24 hours = .25840166 MPH change per hour   
/60min=.00430819444 MPH change per min ……There are 5,280 feet in a mile 
.0043081944 MPH = 22.747266432 feet ( or 6.933366807864
meters) per min   /60 to convert to seconds = .3791 feet per sec/ per second 
change ( or .11554968 meters per sec per sec). This is  a change in velocity of 
 ~4.5 inches per sec/ per sec  Or 11.43 centimeters per sec per second
 
There is now way to consider this amount to be inertial change negligible. The 
effect rate of change regardless of how fast the earth is supposed to be 
traveling because only the rate of any change from the effective inertail 0 is 
measured. 
 
 
This means that the velocity change of the earth going around the sun is not 
just moving 4.5 inches ever second but changing by 4.5 inches per sec. During 
the earths closest approach to the sun (such as traveling in a moving car)if we 
experience 0 velocity change because we are traveling with the earth then 
whatever the current velocity is would be felt as 0. However, the rate of 
change just as in a moving vehicle would be changed if we "give it some gas" 
and in this case the rate of change would be a increase ~4.5 inches every sec 
every sec. This is to say we on second one we increase by 4.5 sec on second two 
we have increased to 9 by second three we have increased to 13.5….the rate 
makes for a exponential distance traveled curve.  In any case this is the rate 
of change. Assume for the sake of argument that your body could not  detect 
that  change rate, current instrumentation however ( acelerometers) are able to 
detect that amount of inertial change
 to almost infinite amounts, and they are not "aetheraly" depemdent).  

Neville Jones <njones@xxxxxxxxx> wrote: 

Not me. 


-----Original Message-----
From: allendaves@xxxxxxxxxxxxxx
Sent: Fri, 18 Jan 2008 07:55:05 -0800 (PST)


Since the earth changes its speed throught it's orbit, has anyone out there 
ever calculated the actual acceleration force changes to the earth as it moves 
back and fourth through its apogee and perigee elliptical orbit around the sun? 



 
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