*From*: Allen Daves <allendaves@xxxxxxxxxxxxxx>*To*: geocentrism@xxxxxxxxxxxxx*Date*: Mon, 21 Jan 2008 07:38:51 -0800 (PST)

Here it is ..quick & rough.... 18.5 miles per second average speed * 60 sec for min * 60 min for MPH = 66600MPH or The ~ avg change over the course of a year is 3.4%* 66600= 2264.4 / 365.4 days=6.2038 MPH per day /24 hours = .25840166 MPH change per hour /60min=.00430819444 MPH change per min ??There are 5,280 feet in a mile .0043081944 MPH = 22.747266432 feet ( or 6.933366807864 meters) per min /60 to convert to seconds = .3791 feet per sec/ per second change ( or .11554968 meters per sec per sec). This is a change in velocity of ~4.5 inches per sec/ per sec Or 11.43 centimeters per sec per second There is now way to consider this amount to be inertial change negligible. The effect rate of change regardless of how fast the earth is supposed to be traveling because only the rate of any change from the effective inertail 0 is measured. This means that the velocity change of the earth going around the sun is not just moving 4.5 inches ever second but changing by 4.5 inches per sec. During the earths closest approach to the sun (such as traveling in a moving car)if we experience 0 velocity change because we are traveling with the earth then whatever the current velocity is would be felt as 0. However, the rate of change just as in a moving vehicle would be changed if we "give it some gas" and in this case the rate of change would be a increase ~4.5 inches every sec every sec. This is to say we on second one we increase by 4.5 sec on second two we have increased to 9 by second three we have increased to 13.5?.the rate makes for a exponential distance traveled curve. In any case this is the rate of change. Assume for the sake of argument that your body could not detect that change rate, current instrumentation however ( acelerometers) are able to detect that amount of inertial change to almost infinite amounts, and they are not "aetheraly" depemdent). Neville Jones <njones@xxxxxxxxx> wrote: Not me. -----Original Message----- From: allendaves@xxxxxxxxxxxxxx Sent: Fri, 18 Jan 2008 07:55:05 -0800 (PST) Since the earth changes its speed throught it's orbit, has anyone out there ever calculated the actual acceleration force changes to the earth as it moves back and fourth through its apogee and perigee elliptical orbit around the sun? --------------------------------- Free 3D Marine Aquarium Screensaver Watch dolphins, sharks & orcas on your desktop! Check it out at www.inbox.com/marineaquarium

**References**:**[geocentrism] Re: acceleration calcs***From:*Neville Jones

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