[geocentrism] Re: Geosynchronous satellites paper

  • From: Neville Jones <njones@xxxxxxxxx>
  • To: geocentrism@xxxxxxxxxxxxx
  • Date: Mon, 2 Jul 2007 13:35:38 -0800

Robert,

In my opinion Eq. (1) is flawed, but I do not have anything to replace it with yet. But if it is flawed, then the figures you correctly derive from Eq. (3) onward are irrelevant.

The ARTEMIS Project Office description of the altitude raising assumes Newton's laws of motion, yes, but it also assumes a heliocentric 'solar system'.

Something is making that satellite slowly orbit the World in the geostationary system. This drift has to be compensated to some degree by the ion-propulsion thruster, but there must be more than simply this going on up there.

Neville.


-----Original Message-----
From: robert.bennett@xxxxxxx
Sent: Sun, 1 Jul 2007 19:09:46 -0400
To: geocentrism@xxxxxxxxxxxxx
Subject: [geocentrism] Re: Geosynchronous satellites paper

 

Neville,

 

The new version has problems.   The speed of the GS geosat is not zero, using your g(x) function.

 

By equating the centripetal force to your gravity force , mg(x), the equivalent of  your eq (3) becomes

 

V2 = Rg(x)

 

Using the value of R and x given: at the GeoStationary Distance, GSD,   => V2  ~= .0081 => V ~= 0.09 km/s

The time to circle the Earth is the period,  T = circ/V = 812 hrs = 33.8 days…. An advance of 10.7 degrees/day.

If the geosat were overhead now, it would disappear below the horizon in 9 days….. hardly a geostationary object or descriptive of the actual geosats.

 

The fundamental problem is that any g(x) you dream up must be zero at the GSD:  g(x=GSD) = 0

 

 

Also, according to the citations, the Artemis team decided to slow down the satellite by ~200 m/s by firing RITA continuously in the opposite direction of motion for 340 days. Since the velocity is inversely proportional to the square root of the radius from Eq(3), this operation would cause the satellite to rise ~ 5000 km.   

 

From the Artemis site;   F= 0.015 N (the constant thrust of Rita)  and payload plus propellant mass ~ 2000 kg. So  Acc = F/m = 7.5 *10-6 m/s2

 

Thus the final velocity, vf =at = 7.5 *10-6 m/s2 * 340 days ~ 220 m/s.

This approximate calculation is sufficiently close to the target speed of 200 m/s to confirm the validity both of the Artemis description of the orbit adjustment and of Newton’s Laws.

 

Robert


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