[AZ-Observing] Re: Slightly off topic, but somehow related to observing
- From: "Rotramel, Rick \(AZ77\)" <rick.rotramel@xxxxxxxxxxxxx>
- To: <az-observing@xxxxxxxxxxxxx>
- Date: Tue, 6 Jun 2006 16:04:34 -0700
The 350 Watts is the "power capacity" of the inverter. The motor is only
drawing 4 Watts from the inverter.
The ~60mA in my inverter below is the current used in the oscillator and
the transformer inside the inverter.
Rick R.
SAC
Rick,
My inverter is 350 Watts, Can I guess that 12v/350Watts would =3D about
34 Ma
for a total of draw of 80 Ma? =20
Thanks
Rick Tejera=20
=20
From: az-observing-bounce@xxxxxxxxxxxxx
[mailto:az-observing-bounce@xxxxxxxxxxxxx] On Behalf Of Rotramel, Rick
=20
Yes, about 36mA AC. But you have to add the inverter current too.
Mine read about 100mA total with the motor, when running.
I've used a 16Ah battery for 3 nights in the past.=3D20
Rick R.
SAC
=20
not sure I'd know how to use it anyway. So, The motor is a 110v, 4 W C
motor. That is powered by a 12 volt battery through an inverter. Now I
looked up Ohm's law and found the Amps=3D3D Power/ Voltage. Given that I =
=3D
get
36.3 Ma. =20
I'm trying to figure out how small a battery I can get away with for a
two
nighter.
Thanks
Rick Tejera=3D20
=20
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