[SI-LIST] Re: power plane inductance
- From: Ray Anderson <Raymond.Anderson@xxxxxxx>
- To: si-list@xxxxxxxxxxxxx
- Date: Mon, 15 Oct 2001 10:46:24 -0700 (PDT)
Anthony-
You can derive the inductance value you want fairly simply with
'back-of-the-envelope' type calculations thusly:
First, calculate interplane capacitance:
Ca= (Er*Eo)/thickness
where Eo= 8.85pF/meter or .2248pF/inch
Er= relative dielectric constant of board dielectric
for example: assume 1 mil thick FR4 with Er=4
Ca = (.2248pf/inch * 4)/1 mil = 900 pF/square inch
Then calculate propagation velocity:
Velocity = Vel_of_light/sqrt(Er)
so Velocity in FR4 with Er=4 would be:
12e9/sec = 12 inches/nsec / sqrt(4) = 6 inches/nsec = 6e9/sec
Now calculate the inductance per square:
La = 1/(Ca * Velocity^2)
So for our example:
La = 1 / (900pf/sq_in * (6e9)^2)
= 1 / (900e-12*36e18) = 30.86pH/square
Knowing this value for a 1 mil thickness you can scale it
with thickness. so for a 4 mil stackup the inductance would be
4X the calculated value or about 120 pH/square
You can go through the numbers to convince yourself, but you
will find the Er of the dielectric doesn't affect the inductance,
which is a function of the thickness of the planes dielectric
separation.
Hope this helps,
Ray Anderson
Sun Microsystems Inc.
>
>Hi Anthony:
>
> You many want to post this question on the si_list -- I bet someone will
>have an answer for you there.
>
> si-list@xxxxxxxxxxxxx
>
> Regards,
> Stephen Peters
> Intel Corp.
>
>
>-----Original Message-----
>From: Anthony Moulds [mailto:anthony@xxxxxxxxxxxxx]
>Sent: Monday, October 15, 2001 7:37 AM
>To: ibis@xxxxxxx
>Subject: power plane inductance
>Importance: High
>Sensitivity: Private
>
>
>Sorry if this is a little off-topic but is there a formula
>for determining the inductance between two points on a power
>plane in a multi-layer pcb (pH/inch2) ?
>
>[I need to check (quantitatively) the max placement distance of decoupling
>caps to fast logic when both are via-ing down to the power/gnd planes.]
>
>
>Thanks.
>
>Anthony Moulds
>
>
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