[SI-LIST] Re: decoupling capacitors
- From: John Barnes <jrbarnes@xxxxxxxxx>
- To: jtalavera@xxxxxx, si-list@xxxxxxxxxxxxx
- Date: Tue, 25 Jun 2002 19:39:22 -0400
Juan,
Sometimes the datasheet will tell you the transient-current requirements
for a part. For example, a microprocessor that has a "sleep mode" will
show a:
* Sudden increase in its core-current draw going from sleep mode to
operating mode. (You usually have no way to control this, except
not using sleep mode.)
* Sudden decrease in its core-current draw going from operating mode
to sleep mode. (If the part has multiple power-down modes, you may
be able to go through these in sequence to reduce this transient.)
For most parts, the transient current draw will be the sum of:
1. Current to drive outputs from low-to-high.
2. Internal "cross-over" currents.
You can estimate the first of these from the sum of the maximum output
short-circuit currents (Ios) for all the outputs that *could* switch
low-to-high at the same time.
Cross-over current is harder to get a handle on. Part of it is due to
the internal design of a chip, and a so-called "low emissions" ASIC
family may actually be worse from a Radiated Emissions standpoint than
a plain ASIC family. (We had this happen at a previous employer. It
was most irksome.)
Especially with CMOS parts, the cross-over current may be very sensitive
to the edge rate (dV/dt) on the inputs. Back in 1972, when the CD4050's
cost $3 each in quantity, I blew up two tubes of the parts experimenting
to determine why they were going "poof" on a controller board we were
developing. I discovered that that they could momentarily draw over
0.3A from a +15V supply:
* With one out of six inputs slowly transitioning from high-to-low or
vice versa.
* With one out of six outputs loaded by more than 100-200pF.
With the package only rated for about 0.3W, many CD4050's wouldn't
survive even one test cycle. Instead there would be a nice crater on
top, over what used to be the chip...
Some datasheets will specify that inputs must transition faster than x
V/ns, to prevent this problem.
I hope this explanation helps.
John Barnes
dBi Corporation
Juan Manuel wrote:
>
> Hi, everybody.
> I'm looking for a method for calculating the appropiated capacitance of
> bypassing capacitors. The most common method is this :
> c=I*N*dt/DV
> The problem that I find in this method is: What is the typical value ofthe I
> ( current needed to switch a output), I know that this current is function of
> the logic families.
> someone knows how obtain these instantanoeus current?
> Thank beforehand.
> juanma
>
> ------------------------------------------------------------------
> To unsubscribe from si-list:
> si-list-request@xxxxxxxxxxxxx with 'unsubscribe' in the Subject field
>
> or to administer your membership from a web page, go to:
> http://www.freelists.org/webpage/si-list
>
> For help:
> si-list-request@xxxxxxxxxxxxx with 'help' in the Subject field
>
> List archives are viewable at:
> http://www.freelists.org/archives/si-list
> or at our remote archives:
> http://groups.yahoo.com/group/si-list/messages
> Old (prior to June 6, 2001) list archives are viewable at:
> http://www.qsl.net/wb6tpu
>
------------------------------------------------------------------
To unsubscribe from si-list:
si-list-request@xxxxxxxxxxxxx with 'unsubscribe' in the Subject field
or to administer your membership from a web page, go to:
http://www.freelists.org/webpage/si-list
For help:
si-list-request@xxxxxxxxxxxxx with 'help' in the Subject field
List archives are viewable at:
http://www.freelists.org/archives/si-list
or at our remote archives:
http://groups.yahoo.com/group/si-list/messages
Old (prior to June 6, 2001) list archives are viewable at:
http://www.qsl.net/wb6tpu
- References:
- [SI-LIST] decoupling capacitors
- From: Juan Manuel
Other related posts:
- » [SI-LIST] decoupling capacitors
- » [SI-LIST] Re: decoupling capacitors
- [SI-LIST] decoupling capacitors
- From: Juan Manuel