[SI-LIST] Re: Why we need to use "Series resistor" at Transmitter?
- From: "Scott McMorrow" <scott@xxxxxxxxxxxxx>
- To: bobperl@xxxxxxxxx
- Date: Tue, 29 Oct 2002 10:35:35 -0800
Bob Perlman wrote:
Hi -
Yes, your bus is terminated, but not with resistors. The PCI spec
puts limits on driver V-I curves, which in turn puts bounds on the
driver output impedance. The bus is series-terminated for all
intents and purposes.
What Bob and Lee say about the PCI bus is misleading.
The PCI bus is generally not a series terminated bus. The bus was
designed to operate on reflected waves without termination and as a
result, the driver output impedance is quite low. PCI busses are
designed to have large amounts of overshoot, undershoot and ringing.
The bus can be de-Q'd using series resistors as attenuation elements,
however, this can only be done with some serious care and analysis.
best regards,
scott
--
Scott McMorrow
Teraspeed Consulting Group LLC
2926 SE Yamhill St.
Portland, OR 97214
(503) 239-5536
http://www.teraspeed.com
>
>There's a difference between using multi-drop, series-terminated
>buses for transmitting synchronous data (usually OK) and using them
>to distribute clocks (usually a nightmare).
>
>Bob Perlman
>
>On Tue, 29 Oct 2002 10:27:58 -0600, Chan, Michael (Eng Hou) wrote:
>
>
>>I don't believe that statement is true. I have PCI bus that has 18 =
>>loadings on it and it is never terminated ( 33MHz ).
>>
>>-----Original Message-----
>>From: Ritchey Lee [mailto:leeritchey@xxxxxxxxxxxxx]
>>Sent: Tuesday, October 29, 2002 10:18 AM
>>To: sandord@xxxxxxxxxxxxx
>>Cc: si-list@xxxxxxxxxxxxx
>>Subject: [SI-LIST] Re: Why we need to use "Series resistor" at
>>Transmitter?
>>
>>
>>The PCI bus, whick all PCs contain, is series terminated. How many
>>
>>
>=
>
>
>>million of
>>those are there? Just have to be careful when you clock data off
>>
>>
>the =
>
>
>>bus.
>>
>>Lee
>>
>>Sandor Daranyi wrote:
>>
>>
>>
>>>>Jim,
>>>>=3D20
>>>>In regard to your comment: "Series termination
>>>>shoulkd NEVER be used wher the path is going to more
>>>>than one input i.e bus configuration.". The ATA/IDE
>>>>interface used in PCs is series terminated at the
>>>>source and is bussed to two loads on data and
>>>>strobe lines. The number of working systems in the
>>>>field is in the millions (every PC that has 2
>>>>drives). The value of the series termination is a
>>>>great consideration (in ATA it is 22-50ohms).
>>>>=3D20
>>>>So series termination in busses can work. Though, I
>>>>recommend a thorough understanding of the system
>>>>before employing this technique.
>>>>=3D20
>>>>=3D20
>>>>Charles Hill, consultant
>>>>
>>>>
>>>I concur. In theory, I agree that it's not "nice", but I've seen
>>>
>>>
>=
>
>
>>series te=3D
>>
>>
>>>rminations (with no parallel termination at the far end) used =
>>>
>>>
>>successfull=3D
>>
>>
>>>y in designs where there were multiple inputs on a trace. "Never"
>>>
>>>
>=
>
>
>>sounds=3D
>>
>>
>>>neat but as with most good rules, there are exceptions.
>>>
>>>I also agree with the caveats. In the examples I remember, the
>>>
>>>
>system =
>
>
>>was =3D
>>
>>
>>>running at a low clock frequency and all the inputs (not more than
>>>
>>>
>3 =
>
>
>>in t=3D
>>
>>
>>>hat case) were close to each other at the end of a long trace. It
>>>
>>>
>was =
>
>
>>of=3D
>>
>>
>>>a daisy-chain topology, i.e. there were no branches on the trace,
>>>
>>>
>to =
>
>
>>min=3D
>>
>>
>>>imize the impedance discontinuities and reflections. The inputs
>>>
>>>
>had =
>
>
>>high=3D
>>
>>
>>>impedance. Of course, one gotta think twice, even thrice, before
>>>
>>>
>=
>
>
>>doing =3D
>>
>>
>>>this on a clock signal.
>>>
>>>Sandor
>>>
>>>---
>>>Sandor Daranyi
>>>Snr Design Engineer
>>>Aristocrat Technologies Australia
>>>
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>>
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- [SI-LIST] Re: Why we need to use "Series resistor" at Transmitter?
- From: Lieby David