[SI-LIST] Lower epsilon achieves lower crosstalk

We could achieve lower crosstalk by using dielectric with lower
permittivity, while keeping *Z0* as a constant.


I'm new in SI, my understanding about this question is:



If we use dielectric with lower permittivity while keeping *Z0* as a
constant.

We need to reduce *h *to maintain a constant *C*, because *C*= *epsilon***w*
/*h*, and *Z0*=1/*vp*/*C*.



Since *Z0* = sqrt(*L/C*), to keep* Z0* as a constant, the stripe line need
to adjust it?s current distribution to maintain a constant *L*.



Considering the loop area decrease because *h* is reduced, the current
distribution should be more tighter to maintain a constant *L*.



Finally the tighter current distribution on the returning pass results in
the reduction of the cross talk.



Are these correct? I will appreciate your help



Best Regards

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