[SI-LIST] Re: Loss tangent calculation
- From: "Tabatchnick, Justin" <justin.tabatchnick@xxxxxxxxx>
- To: <si-list@xxxxxxxxxxxxx>
- Date: Thu, 3 Apr 2003 14:53:48 -0800
Hi;
I think your formula is wrong tan d =3D ( conductivity + omega *
dielectric loss constant)/(Omega * permittivity)
Justin Tabatchnick
Intel , Sacramento
-----Original Message-----
From: atifshamimkhan [mailto:ashamim@xxxxxxxxxxxxxxx]=20
Sent: Thursday, April 03, 2003 11:58 AM
To: si-list@xxxxxxxxxxxxx
Subject: [SI-LIST] Loss tangent calculation
Hi
I am designing an antenna on Si substrate at 24 GHz.I want to
calculate the Loss tangent for this substrate .I have the following
info
Resistivity =3D 300 ohm-cm (for silicon substrate )
I calculate it as follows: conductivity =3D 1/ resitivity
Also loss tangent (Tan d)=3D conductivity / (epsilon * 2 *pi * f )
where Epsilon (r) for silicon is 12 and f is 24 GHz.In this way I get
=20
Tan d =3D 0.25=20
I dont know whether this calculation is right or not.My question is if
this is not the right way then how can I calculate the Loss tangent
from resistivity only and secondly if this is right then why the loss
tangent decreases with the increase in fequency.
Thanks=20
Atif
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=20
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