[SI-LIST] Re: Jitter transfer vs. accumulation
- From: steve weir <weirsi@xxxxxxxxxx>
- To: "Tang, George" <George.Tang@xxxxxxx>,<si-list@xxxxxxxxxxxxx>
- Date: Wed, 21 Mar 2007 20:28:51 -0700
George, thanks for the reply.
At 05:02 PM 3/21/2007, you wrote:
>Steve,
>
>Please see comments in {{{{{ }}}}} below.
>
>
>George
>
>
>snip
>-----Original Message-----
>From: steve weir [mailto:weirsi@xxxxxxxxxx]=20
>Sent: Tuesday, March 20, 2007 4:10 AM
>To: Tang, George; Alfred P. Neves; Chris Cheng; si-list@xxxxxxxxxxxxx
>Subject: Re: [SI-LIST] Re: Jitter transfer vs. accumulation
>
>George, please correct me if I am wrong, but I believe:
>
>1) That the inverter gain K is both temperature and supply voltage
>dependent.
>
>{{{{{True, not a function of time. }}}}}
>
Good. Then do we also agree that when the supply voltage and
temperature both vary with time that the gain does as well? If not why?
>2) That even in an isothermal, constant supply, and zero noise Vref=20
>environment, running open-loop that in the limit any single VCO=20
>output interval can vary from epsilon*ring_stages to approximately=20
>Vcc/Vths_nom*UI*ring_stages.
>
>{{{{{You CANNOT rewrite the laws of physics with your funny formula.
>The input sensitivity (in mV) is not proportional to VCC voltage nor
>inversely proportional to Vth. Throwing such formulae around does not
>fool people into believing you. }}}}}
George there is no attempt to "fool people". Please keep the
discussion on a professional level.
The minimum period for one inverter in the presence of a large enough
shot noise pulse is the inverter minimum delay time epsilon, is it not?
An arbitrarily large noise shot pulse can only defer a transition by
a maximum amount of time. If you object to the approximation of
Vcc/Vths I am open to discussion of alternative approximations.
>Maybe I don't understand what you mean by
>
>"My assertion is that when temperature,
>voltage, low noise level and fixed noise frequency parameters are all in
>steady-state condition, the open-loop VCO output jitter shall be
>constant."
>
>{{{{{The output RMS jitter shall be constant. When we talk about PLL or
>VCO jitter, we usually talk about the RMS jitter. Phase jitter is
>meaningless unless you specify the sample size. }}}}}
>
>
>That sounds like Dj induced from power supply feedback.
>
>
>{{{{{Whatever the cause, the result is the same. }}}}}
OK I think we agree there is a big difference between peak jitter and
RMS jitter. So, I think we can put that aside and concentrate on RMS jitter.
>My interpretation is that even in this pristine environment of a=20
>perfect power supply the oscillator exhibits unbounded Rj. If it is=20
>bounded, what limits it?
>
>{{{{{Alfred made the initial postulate that open-loop VCO has rms jitter
>governed by his funny equation Y=mX + b, where Y is the rms jitter, X is
>the time duration of measurement, and m > 0. This shows that as time
>goes to infinity, the rms jitter of the open-loop VCO also goes to
>infinity. He further claimed that with the feedback loop of the PLL,
>the rms jitter became bounded. You don't think Alfred was crazy enough
>to make the mistake of comparing phase jitter of VCO to the RMS jitter
>of the PLL, do you? That will be comparing apples to bananas, let alone
>oranges.
>
>My claim is that both VCO rms jitter and PLL rms jitter are bounded, and
>the closed-loop feedback circuit simply attenuates the open-loop rms
>jitter. Both circuits have unbounded phase jitters. }}}}}
So it sounds to me that we agree that Rj is unbounded. My experience
agrees with Al's assertion that due to Rj, RMS jitter does creep
upwards with time. This is the evil of the 1/f noise corner
exhibited by every DC amplifier I have encountered. If noise density
/ square root frequency were the RMS value wouldn't creep. What is wrong here?
I have to agree with you that an indefinite divided by a definite is
still indefinite. Al will have to address whether he was saying that
feedback bounds peak jitter, and if so why.
>In my world, ( which may be perverse ) the only way that we get to=20
>bound Rj is to bound the number of UIs, and we don't get to do that=20
>until we close the feedback loop.
>
>
>{{{{{Sorry, another funny theory of yours. RJ is a statistical
>probability. Bounding the number of UIs does not bound the peak-to-peak
>RJ. Closing the feedback loop does not bound RJ p-p. }}}}}
>
I acknowledged that I mispoke on this in my private e-mail to
you. The likelihood that an event outside some magnitude will occur
shrinks with reduced exposure. Applying feedback cannot reduce the
limit which remains indefinite. It does however effectively reduce sigma.
>In my mind this goes back to=20
>Chris' issue which is that from the loop cut-off up to 1/UI the VCO=20
>accumulates phase error based on thermal, power supply noise, and=20
>reference voltage noise disturbances with little or no=20
>attenuation. It is only well within the closed loop B/W that=20
>feedback diminishes those error terms WRT the apparent reference=20
>timing source. Is this incorrect?
>
>
>{{{{{No. Phase jitter is always accumulated regardless open-loop or
>closed-loop. Closing the loop does attenuate the phase error within the
>bandwidth, but RMS RJ does not go to zero. }}}}}
>
We agree that feedback cannot drive jitter to zero. I remain at odds
with your blanket assertion that phase jitter accumulates in a closed
loop as well as an open loop. Jitter is a noise term, and all my
references state that a feedback loop works to reduce noise terms of
the elements within the loop. Do you have a reference as to why this
would not be so in this situation?
It appears we agree that the loop acts to reduce phase error which is
what we care about and where Chris' complaint came from. We appear
to also agree that as we slide down the GBW curve the amount of
correction shrinks. Do we agree that well above the 0db crossing the
loop does almost nothing to adjust the VCO phase to match the
incoming data stream? If we agree then I think Chris' point is
made. If we don't, I would like to know why. It may be for the
particular standards that Chris is unhappy about that other concerns
drove the cut-off frequencies selected. But from the narrow
perspective of the PLL bandwidth impact on CDR function I see his point.
>If so, why? Absent feedback, I=20
>expect the each inverter in the oscillator to exhibit 1/f noise like=20
>any other amplifier no matter how clean the power supply is. Do you=20
>agree? If not, why?
>
>{{{{{Sure. But with feedback, the same is still true that the random
>noise is still present. That is not the point of the argument. }}}}}
>
I am not sure if we agree that feedback attenuates all types of noise. Do we?
>I agree that designing a stable VCO and feeding it with clean low=20
>impedance power are important towards achieving low jitter. But I am=20
>having difficulty following the apparent idea that achieving those=20
>goals eliminates jitter components as opposed to reducing them to=20
>small values. Is there a conflict between semantics of "very small"=20
>and "zero"?
>
>
>{{{{{I never said that jitter can be eliminated. I only said that RMS
>jitter is bounded for both VCO and PLL. Alfred made the assertion that
>VCO has unbounded rms jitter, but PLL has bounded rms jitter. The funny
>equations you guys put out do not help with your arguments at all.
>}}}}}
>
Al is very capable and knowledgeable in this area. I do not speak
for him. It would be a lot easier to reach a common understanding if
you could tone down the open hostility.
>Regards,
>
>
>Steve.
snip
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- From: Alfred P. Neves
- [SI-LIST] Re: Jitter transfer vs. accumulation
- From: Tang, George
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- » [SI-LIST] Re: Jitter transfer vs. accumulation
- [SI-LIST] Re: Jitter transfer vs. accumulation
- From: Alfred P. Neves
- [SI-LIST] Re: Jitter transfer vs. accumulation
- From: Tang, George
- [SI-LIST] Re: Jitter transfer vs. accumulation
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