[program-java] Re: Java: Precedence
- From: "Sina Bahram" <sbahram@xxxxxxxxx>
- To: <program-java@xxxxxxxxxxxxx>
- Date: Tue, 7 Sep 2010 16:54:01 -0400
I hate to disagree, but it absolutely will. I just compiled and tested a
solution to verrify what I thought I already knew.
You can shadow variables all you like.
For a conceptual aid, think of how setters work. Often time, the argument name
is the same as the inner name, leading to code like
this.
public void setAge(int age) {
this.age = age;
}
Take care,
Sina
-----Original Message-----
From: program-java-bounce@xxxxxxxxxxxxx
[mailto:program-java-bounce@xxxxxxxxxxxxx] On Behalf Of Jeffrey Fidler
Sent: Tuesday, September 07, 2010 4:30 PM
To: program-java@xxxxxxxxxxxxx
Subject: [program-java] Re: Java: Precedence
Hello, Jim and all. The Java compiler will not allow you to redeclare a local
variable having the same identifier value as the
instance variable identifier as you have supplied in your example. Although
C++ will allow this sort of scope hiding, Java will
not.
Thanks & kind regards,
Jef
----- Original Message -----
From: "Sina Bahram" <sbahram@xxxxxxxxx>
To: <program-java@xxxxxxxxxxxxx>
Sent: Tuesday, September 07, 2010 4:15 PM
Subject: [program-java] Re: Java: Precedence
Jim,
My appologies, no slap down intended. Sorry, was probably far too Socratic
in my response.
Care to post the whole code?
Take care,
Sina
-----Original Message-----
From: program-java-bounce@xxxxxxxxxxxxx
[mailto:program-java-bounce@xxxxxxxxxxxxx] On Behalf Of Corbett, James
Sent: Tuesday, September 07, 2010 3:53 PM
To: 'program-java@xxxxxxxxxxxxx'
Subject: [program-java] Re: Java: Precedence
Hi:
Obviously zero. ...Ok, the reason I ask was because in this piece of code
that I've inherited x for lack of a better name is used in
at least 30 places in the class and the class level x is declared as
transient. I'm trying to figure this mess out and thought I
would ask the initial question with out the slap down.
Jim
-----Original Message-----
From: program-java-bounce@xxxxxxxxxxxxx
[mailto:program-java-bounce@xxxxxxxxxxxxx] On Behalf Of Sina Bahram
Sent: September 7, 2010 15:19
To: program-java@xxxxxxxxxxxxx
Subject: [program-java] Re: Java: Precedence
Jim,
You should be able to answer this question yourself based on first
principles.
Let's examine what you have.
You have a method, and in there you declare a variable named x. absolutely
nothing else matters, even a million other definitions of
x in a million other scopes, because the next line returns x, and the x in
the immediate scope is the variable you just defined;
thus, 11 is returned.
Also, don't do x=0 when defining your variable. if you want to assign a
value to x, then do it in your constructor. Furthermore, x
is an int, which means it defaults to 0.
What if we change that line to "return this.x;"? Can you tell me what value
is returned?
Take care,
Sina
________________________________
From: program-java-bounce@xxxxxxxxxxxxx
[mailto:program-java-bounce@xxxxxxxxxxxxx] On Behalf Of Corbett, James
Sent: Tuesday, September 07, 2010 2:21 PM
To: 'program-java@xxxxxxxxxxxxx'
Subject: [program-java] Java: Precedence
Hello all:
I know y'all say don't do that but let's just pretend.
If a member is declared private to the class such as
Public Class MYClass {
Private int x = 0;
Public MYClass() {
}
Public int getX () {
int x = 11;
return x;
}
}
What would you expect to have returned as a value of .getX()?
Jim
James M. Corbett
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