[program-java] Re: Java: Precedence
- From: "Sina Bahram" <sbahram@xxxxxxxxx>
- To: <program-java@xxxxxxxxxxxxx>
- Date: Tue, 7 Sep 2010 15:18:33 -0400
Jim,
You should be able to answer this question yourself based on first principles.
Let's examine what you have.
You have a method, and in there you declare a variable named x. absolutely
nothing else matters, even a million other definitions of
x in a million other scopes, because the next line returns x, and the x in the
immediate scope is the variable you just defined;
thus, 11 is returned.
Also, don't do x=0 when defining your variable. if you want to assign a value
to x, then do it in your constructor. Furthermore, x
is an int, which means it defaults to 0.
What if we change that line to "return this.x;"? Can you tell me what value is
returned?
Take care,
Sina
________________________________
From: program-java-bounce@xxxxxxxxxxxxx
[mailto:program-java-bounce@xxxxxxxxxxxxx] On Behalf Of Corbett, James
Sent: Tuesday, September 07, 2010 2:21 PM
To: 'program-java@xxxxxxxxxxxxx'
Subject: [program-java] Java: Precedence
Hello all:
I know y'all say don't do that but let's just pretend.
If a member is declared private to the class such as
Public Class MYClass {
Private int x = 0;
Public MYClass() {
}
Public int getX () {
int x = 11;
return x;
}
}
What would you expect to have returned as a value of .getX()?
Jim
James M. Corbett
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