-=PCTechTalk=- Re: MSCDEX command parameters

Hi Ted,
According to an old Creative CD-ROM drive installation manual, the syntax 
of the MSCDEX command is:

C:\path\MSCDEX.EXE /D:device /M:xx [/L:drive] [/E] /V

where:
path is the directory for CDROM software
/D:driver is the name of the CD-ROM drive, must be identical to the device 
name in the CONFIG.SYS file
/E alows the use of expanded memory, if available
/K directs MS-DOS to recognize drives encoded in Kanji
/S enables sharing of CD-ROM drives in Windows for Workgroups or MS-NET servers
/V displays summary of RAM and memory allocation at boot
/L:letter is the lettter assigned to the CD-ROM drive; if not specified the 
next available letter is used
/M:xx is the number of buffers for temporary storage of data. xx ranges 
from 2 to 30. CD-ROM performance increases with the value of xx; too many 
buffers may impact programs with large memory requirements.

Keep in mind this refers to DOS memory (the first 640Kb) and not to the 
total RAM installed in the machine.
Best,
Wilson

At 17:25 29/08/02 +0100, ted clark wrote:

>does anyone have any ideas on this;-
>
>I have this command in my 'autoexec.bat'
>
>"rem TShoot: - By Windows Setup -
>C:\WINDOWS\COMMAND\MSCDEX /v /D:ECSCD003 /M10"
>
>the 'tshoot' is because I've disabled it in MSCONFIG and
>I did this because, when booting, this command is
>followed
>by 'bad command'.
>
>what does the   '\v'   mean and  '/M10'   ??
>
>I have found [for general interest] that 'MSCDEX' is the
>dos CD driver control and  'D:ECSCD003' is the driver.
>! anyone ! please correct me if I have got it wrong !
>
>all you old DOS veterans out there please set me
>straight on this
>
>cheers
>Ted
>
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