On Thu, Nov 13, 2008 at 3:21 AM, Mark W. Farnham <mwf@xxxxxxxx> wrote: > and you can spend your time figuring out the best way to > generate a list of values from 0 (or 1) through the max value. (That might > be perl [grinning in Jared's direction] This works - just change the argument 2000 to whatever. The second argument (end of the line) is the delimiter to print. perl -e '@x=(1..$ARGV[0]);print join(qq{$ARGV[1]},@x)' 2000 ' ' :)