You didn't give the algorithm but something like this may work:select to_char(sysdate,'yyyy-mm-dd hh24:mi'), case when to_number(to_char(sysdate,'mi')) between 0 and 29 then to_char(sysdate,'yyyy-mm-dd hh24')||':00' else to_char(sysdate,'yyyy-mm-dd hh24')||':30' end from dual;
This "rounds back", if you want to round you may have to adjust it to increase the hour as well.
Regards, Greg Rahn http://structureddata.org -------- Original Message -------- Subject: how to trunc date column to half an hour From: "Derya Oktay" <deryaoktay@xxxxxxxxx> To: oracle-l <oracle-l@xxxxxxxxxxxxx> Date: 3/6/2007 10:16 AM
Hi All, Is there a way of displaying date columns, truncated to half an hours. For example: select trunc(sysdate,'HH') from dual; Regards, Derya. FYI. We are usig this sort of functions in group by expressions.PS. Ghassan thank you for your answer regarding local/global index es in partitions.
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