Hi Mark,
Excellent. That's the answer I wanted. Thank you so much.
SELECT name, SUM((CASE WHEN GROUPS LIKE 'GROUP A%' THEN 1 WHEN GROUPS LIKE 'GROUP B%' THEN 2 WHEN GROUPS LIKE 'GROUP dev%' THEN 4 END)) FROM test GROUP BY name HAVING SUM((CASE WHEN GROUPS LIKE 'GROUP A%' THEN 1 WHEN GROUPS LIKE 'GROUP B%' THEN 2 WHEN GROUPS LIKE 'GROUP dev%' THEN 4 END)) = (SELECT SUM((CASE WHEN GROUPS LIKE 'GROUP A%' THEN 1 WHEN GROUPS LIKE 'GROUP B%' THEN 2 WHEN GROUPS LIKE 'GROUP dev%' THEN 4 END)) FROM test WHERE name ='Marry');
Dave
From: "Mark W. Farnham" <mwf@xxxxxxxx> To: <davidb158@xxxxxxxxxxx>, <oracle-l@xxxxxxxxxxxxx> Subject: RE: SQL help needed Date: Mon, 10 Jul 2006 12:09:31 -0400
name group group_value M A 1 M B 2 M dev 4 D etc.......
select name, sum(group_value) from test group by name having group_value = (select sum(group_value) from test where name = 'M'));
should work (off of the top of my head and my typing is not tested.)
Notice those group_values are disjoint powers of two. You could craft a
decode on your existing data to do the same thing. If you don't enforce
uniqueness on name-group tuples this could generate false answers, and you'd
have to make the statement more complicated.
-----Original Message-----
From: oracle-l-bounce@xxxxxxxxxxxxx [mailto:oracle-l-bounce@xxxxxxxxxxxxx]On
Behalf Of David Boyd
Sent: Monday, July 10, 2006 11:18 AM
To: oracle-l@xxxxxxxxxxxxx
Subject: SQL help needed
Hi List,
I was wondering if a SQL statement is possible for following query.
The name of the table is test. It has following data:
name group Marry group A 1-1 Marry group B 1-2 Marry group dev 1-1 Ann group A 2-3 Dave group A 2-3 Dave group B 4-1 Dave group dev 3-2
I want to find out the names that are in the exact same groups as 'Marry'.
The number in the group has to be ignored. For the above data, the query
should return 'Dave' only since both Marry and Dave are in group A, group B,
and group dev.
Thanks for any input advance.
Dave
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