RE: Question on how cardinality is calculated.

All,
 
Thanks to those who answered, the majority pointing out that it is 5% of the 
number of rows.
 
The oracle version is 9.2.0.8
 
To build on the information provided, the actual query used in an application 
does the following:
 
select cases.a, cases.b, cases.c, cases.case, enquiry.a, enquiry.b, enquiry.c
from cases, enquiry
where
enquiry.id = cases.id
and upper(case) like '%123456%';

Now the user always enters six digits which I know identifies 1 record in the 
cases table, but because Oracle uses a cardinality of 5553 for this it performs 
a hash join to the enquiry table, even though only one record will match in the 
enquiry table. The enquiry table contains 1.4 million record so it takes ~5 
seconds.

Would it be advisable to put a hint on the query to either use a nested loop 
which allows the query to use an index to retrieve the data from enquiry table. 
Or use a cardinality hint since I know we will not be returning 5553 rows which 
will also allow the use of an index.

 

Thanks

Ronnie


________________________________

From: oracle-l-bounce@xxxxxxxxxxxxx on behalf of Jonathan Lewis
Sent: Thu 1/10/2008 4:22 PM
To: Ronnie Doggart; oracle-l@xxxxxxxxxxxxx
Subject: Re: Question on how cardinality is calculated.




5% of num_rows

Regards

Jonathan Lewis
http://jonathanlewis.wordpress.com <http://jonathanlewis.wordpress.com/> 

Author: Cost Based Oracle: Fundamentals
http://www.jlcomp.demon.co.uk/cbo_book/ind_book.html

The Co-operative Oracle Users' FAQ
http://www.jlcomp.demon.co.uk/faq/ind_faq.html


----- Original Message -----
From: "Ronnie Doggart" <ronnie_doggart@xxxxxxxxx>
To: <oracle-l@xxxxxxxxxxxxx>
Sent: Thursday, January 10, 2008 3:06 PM
Subject: Question on how cardinality is calculated.


All

Does anyone know how Oracle calculates the cardinality of a query such as:

Select * from table_1 where upper(case) like '%12345%';

Execution Plan
----------------------------------------------------------
   0      SELECT STATEMENT Optimizer=CHOOSE (Cost=131 Card=5553 Bytes=621936)
   1    0   TABLE ACCESS (FULL) OF 'TABLE_1' (Cost=131 Card=5553 Bytes=621936)

Oracle calculates that it is expecting 5553 rows from this query but I
know it will only return 2.

How does it do its estimate ?



Ronnie Doggart


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