Re: Oracle CRS and Split Brin

node1 loses its interconnect - this is where I understand the misscount 
parameter comes into play. The oracle cssd process checks for the network and 
disk heartbeat. Misscount represents the maximum time that a heartbeat can 
be missed before entering into a cluster reconfiguration to evict a node. So if 
node1 were to lose its interconnect (regardless of being the master it should 
be evicted shouldn't it?). This would leave one of the other(s) to become the 
new master - which one becomes the master - i guess Kevin's already answered 
that one.
When the evicted node is back in business - i assume you mean its interconnect 
is now fixed, a cluster reconfiguration should take place adding that node back 
into the cluster.
I'm sure once Kevin has a glance over this he'll correct me where I'm wrong.

Naqi

----- Original Message ----
From: amonte <ax.mount@xxxxxxxxx>
To: Kevin Closson <kevinc@xxxxxxxxxxxxx>
Cc: naqimirza@xxxxxxxxx; oracle-l@xxxxxxxxxxxxx
Sent: Thursday, 29 March, 2007 4:32:02 AM
Subject: Re: Oracle CRS and Split Brin

That is what I mean Kevin, how does a node know which one will be evicted.

 

For instance if node 1 (the lower node) loses its interconnect what happens? 
The other(s) will be evicted? What happens if the evicted node(s) is back to 
business. Because it cannot contact node 1 through network what will happen? 
(node 1 lost private network)


 

How does Voting Disk help to determine Split Brain?

 

Thanks

 

Alex

 

On 3/28/07, Kevin Closson <kevinc@xxxxxxxxxxxxx> wrote:



 





When the master node looses its private network, the surviving node becomes the 
master, reconfiguration of the cluster takes place - the old master is ejected 
from the cluster configuration - and rebooted. The following can be seen in its 
crsd.log file (this is for the crs component of the oracle clusterware, 
responsible for managing oracle resources):
.
I AM THE NEW OCR MASTER at incar 6. Node Number = 1


..[…lots good CRS stuff deleted…]

…This was a very good follow up, but the question was about split brain. Split 
brain is when there is an equal number of "survivors" and both "think" they are 
the sole survivor. I think the original post was asking how Oracle determines 
who gets to anoint themselves the new master in a split brain scenario. I have 
not seen the full algorithm Oracle uses documented anywhere on the net so if 
someone has, please let us know. There are a lot of cluster implementations out 
there. One common approach is to maintain knowledge of the IP addresses of 
members and use the lowest IP node as one of the factors in choosing the winner 
in a SB scenario.  That is not how CRS does it though as has become evident in 
a thread I've had with a reader of my blog. In his 2 node case his CRS master 
was also the lowest IP and in a meltdown scenario, the other node was chosen as 
the sole survivor. That really surprised me.


I think all I've said is Oracle is not telling us what the full algorithm is 
for survivorship in a true split-brain scenario.


There are some clusterware topics here: 
http://kevinclosson.wordpress.com/kevin-closson-index/real-application-clusters-related-topics/
 

Such as 
http://kevinclosson.wordpress.com/2007/01/10/comparing-10201-and-10203-linux-rac-fencing-also-fencing-failures-split-brain/

 



 











                
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