[mso] Re: Access 2002: Date Filter Formula Calculation Help Needed!

Cathy--

You gotta love the DateDiff function. Give this a try:

DataFilter: Iif(DateDiff('yyyy', [Year], Now()) > 2, "Yes", "No")

--Jim 

-----Original Message-----
From: mso-bounce@xxxxxxxxxxxxx [mailto:mso-bounce@xxxxxxxxxxxxx] On Behalf
Of Cathy.Evans@xxxxxxxxx
Sent: Wednesday, August 17, 2005 6:36 AM
To: mso@xxxxxxxxxxxxx
Subject: [mso] Access 2002: Date Filter Formula Calculation Help Needed!


My table has a 'year' field with results that are either null or 2001, 2002,
etc.  It also has a second field with status, either open or closed.
I am trying to build a filter that says if the project has been closed for
more than 2 years, remove it from the result.   I'm having problems with
the 'more than 2 years' part of the filter. How do I say if [year] is
greater than Now() - 2 years, and if [status] is "Closed", return a 'yes'
value, otherwise, 'no'.

Here is my pitiful attempt at the start of the date portion of this filter,
which is only giving me a 'No' on the null values:

DateFilter: IIf([Year]<Now()-730,"Yes","No")

Appreciate any help, thanks, Cathy



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