[mso] Re: Access ???

Waaahhh, ha, hic, sob...my way isn't best...barely better than doing it by
hand.  I'm soooo frustrated!  All this terrific technology in front of me
and I haven't a clue how to take advantage of it.  Well, actually, I do have
a clue, two even, which I got from this list so please, don't any of y'all
give up on me.  I'm learning, rather like the first parasite dragging itself
out of the primordial ooze but still, it's progress.  /gl

-----Original Message-----
From: Colli, Anthony G [mailto:Anthony.Colli@xxxxxxx] 
Sent: Tuesday, June 25, 2002 2:43 PM
To: 'mso@xxxxxxxxxxxxx'
Subject: [mso] Re: Access ???


Glenda-

 I just spent a few minutes trying to get a crosstab to work too. I didn't
have much luck either. Maybe your way is the best way. The northwind
database has a pretty good example of a crosstab query, check it out. MS
Access uses JET as a database, and it is not ANSI compliant. If it were you
could write your own crosstab query using SELECT CASE statements in the sql.


-Anthony

-----Original Message-----
From: Glenda Wells [mailto:gwells@xxxxxxxxxxx]
Sent: Tuesday, June 25, 2002 1:40 PM
To: 'mso@xxxxxxxxxxxxx'
Subject: [mso] Re: Access ???



I know I'm missing a step somewhere but...

I tried doing a Pivot Table in Excel and that didn't work.

Here's a sample of what I started with.  3 ID for BEST OOO3, 2 ID for BEST
0004 and 1 ID for CARS 2000.

ID      Bldg    Room    Assignment      Number
757     BEST    0003    BEST 0003       1
6760    BEST    0003    BEST 0003       1
2356    BEST    0003    BEST 0003       1
4448    BEST    0004    BEST 0004       1
9922    BEST    0004    BEST 0004       1
7017    CARS    2000    CARS 2000       1

This is the result I need
Assignment      Roomie1 Roomie2 Roomie3
BEST 0003       757             6760            2356
BEST 0004       448             9922
CARS 2000       7017

When I tried an Access Crosstab query just now, with Assignment as Row
Heading and ID as Column, got error too many crosstab column headers.

There's 762 assignments and 1,391 ID

-----Original Message-----
From: Colli, Anthony G [mailto:Anthony.Colli@xxxxxxx] 
Sent: Tuesday, June 25, 2002 1:21 PM
To: 'mso@xxxxxxxxxxxxx'
Subject: [mso] Re: Access ???


Glenda-


 Now I understand perfectly. A Crosstab query is what you are looking for.
It's like a pivot table in Excel. 

-Anthony

-----Original Message-----
From: Glenda Wells [mailto:gwells@xxxxxxxxxxx]
Sent: Tuesday, June 25, 2002 1:16 PM
To: 'mso@xxxxxxxxxxxxx'
Subject: [mso] Re: Access ???



Just in case anyone is interested, here's an example of the result.
Assignment is a concatenate of Building and Room. Roomie 1 is FIRST and
Roomie2 is LAST in the aggregate query below where I ended up with 625
records with 2 unique ID per Assignment.

Assignment      Roomie1 Roomie2
BEST 0001       16              207
BEST 0004       448             922
CARSON 3101     617             544
CARSON 3102     2813            5796

SELECT tblRoomAssignmentByPIDM.Assignment,
First(tblRoomAssignmentByPIDM_1.SLRRASG_PIDM) AS Roomie1,
Last(tblRoomAssignmentByPIDM_1.SLRRASG_PIDM) AS Roomie2 INTO tblRoomie1 FROM
tblRoomAssignmentByPIDM INNER JOIN tblRoomAssignmentByPIDM AS
tblRoomAssignmentByPIDM_1 ON tblRoomAssignmentByPIDM.SLRRASG_PIDM =
tblRoomAssignmentByPIDM_1.SLRRASG_PIDM
GROUP BY tblRoomAssignmentByPIDM.Assignment
HAVING (((Count(tblRoomAssignmentByPIDM.Number))=2))
ORDER BY tblRoomAssignmentByPIDM.Assignment;

Hi All. 

Our email system was out of commission for a while so just getting back and
want to catch up on my roommate table problem.

I have 1,391 persons assigned to 762 rooms:  135 Singles, 625 Doubles, 2
Triples.

The original list consists of the person ID, the building code and the room
number.

What I did was this for the double rooms, twice.  The result is 2 temporary
tables with 625 records each.

SELECT tblRoomAssignmentByPIDM.Assignment,
First(tblRoomAssignmentByPIDM_1.SLRRASG_PIDM) AS Roomie1,
Last(tblRoomAssignmentByPIDM_1.SLRRASG_PIDM) AS Roomie2 INTO tblRoomie1 FROM
tblRoomAssignmentByPIDM INNER JOIN tblRoomAssignmentByPIDM AS
tblRoomAssignmentByPIDM_1 ON tblRoomAssignmentByPIDM.SLRRASG_PIDM =
tblRoomAssignmentByPIDM_1.SLRRASG_PIDM
GROUP BY tblRoomAssignmentByPIDM.Assignment
HAVING (((Count(tblRoomAssignmentByPIDM.Number))=2))
ORDER BY tblRoomAssignmentByPIDM.Assignment;

I appended the result of the 2 queries to a table structure that gives
Roomie1 and Roomie2 ID's the title of Main which is then linked via quires
by the ID's to other tables for name and address information.

Kludgy but it works.  But there has to be a programmatic was to accomplish
the task and include the singles and triples as well.

The single rooms are simple, and the 2 triples, I'll do by hand.
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