[interfacekit] Re: HELP!
- From: Erik Jaesler <erik@xxxxxxxxxxxxxx>
- To: interfacekit@xxxxxxxxxxxxx
- Date: Tue, 17 Feb 2004 13:37:21 -0800
It's a bitfield. It declares test as a struct with members which are 1
bit, 2 bits, and 3 bits wide. The funky output is the result of the
value getting truncated to fit the bit widths. For example, in the
first assignment, 7 (binary: 111) ends up like this:
x.a == 1 (binary: 1)
x.b == 3 (binary: 11)
x.c == 7 (binary: 111)
The second assignment is weird because the value gets chopped down to a
single bit by the assignment to x.a before getting assigned to x.c.
HTH,
e
Adi Oanca wrote:
Hi!
I encountered this sample and I can't understand what it does! I
searched(my archive of C books) but found no references to something
like this, so PLEASE help me understand what this means and what happens
here...
#include<stdio.h>
struct test{
unsigned a:1, b:2, c:3;
};
void main(){
struct test x;
x.a = x.b = x.c = 7;
printf("%d %d %d\t", x.a, x.b, x.c);
x.c = x.a = x.b = 7;
printf("%d %d %d", x.a, x.b, x.c);
}
The result is: 1 3 7 1 3 1.
What's the meaning of: a:1, b:2, c:3 ?
Thank you,
Adi.
---------------------------------------------------------------
Cauta-ti perechea pe http://dating.acasa.ro
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- » [interfacekit] Re: HELP!
Hi!
I encountered this sample and I can't understand what it does! I searched(my archive of C books) but found no references to something like this, so PLEASE help me understand what this means and what happens here...
#include<stdio.h>
struct test{
unsigned a:1, b:2, c:3;
};
void main(){
struct test x;
x.a = x.b = x.c = 7;
printf("%d %d %d\t", x.a, x.b, x.c);
x.c = x.a = x.b = 7;
printf("%d %d %d", x.a, x.b, x.c);
}
The result is: 1 3 7 1 3 1.
What's the meaning of: a:1, b:2, c:3 ?
Thank you, Adi.
--------------------------------------------------------------- Cauta-ti perechea pe http://dating.acasa.ro
- [interfacekit] Re: HELP!
- From: Adi Oanca
- [interfacekit] HELP!
- From: Adi Oanca