EUREKA!!......A translational orbit still produces a rotational effect!...The punch line is .... 1. the axis of the rotation shifts from the body that is being orbited to the center of the body in the translational orbit.... 2. It reverses the effects of the rotational effects. That is to say that a clockwise orbit will produce counter clockwise rotational impression on film where if the translational orbit is clockwise then the rotational effects on film will be clockwise!.. The fact that the earth's has a translational orbit around the sun cannot and will not hide a rotation around the NCP which is offset from the nightly NEP by 23 degrees.. YES, Im already fully aware of ALL the previous as well as possible objections.....i was able to isolate each and every single one.........I have now found the way to prove it as well as demonstrate how it can be accomplished in the real world ......The solution is remarkably "simple" but extremely hard to visualize due to the complexities of the kinematics........If you imagine a set of crosshairs they have a up/ down equal distant mark as well as a left and right equal distant mark....The trick is understanding that the back and fourth motion of the sun by 23 degrees annually is nothing more then up/down deviations from that up/down center mark.....The key is as long as the right/ left center mark does not deviate we can still get our rotation around a axis that lay parallel to a axis that is perpendicular and runs through the suns (ecliptic deviation/ path) since it lay perpendicular to the up/down centerline on our cross hairs, because it lays 23 degrees offset ..this is true because any rotation around the sun or ecliptic is not dependent on the north south deviation of the sun/ecliptic ..the rotation & it’s effects are around a axis that lay perpendicular to that deviation. Yes we have to have a camera that does not move with respect to that ecliptic deviation….I will show but we should already know exactly how to accomplish that… .......the proof is quite detailed i will lay out the fundamentals bit by bit so we don’t get confused by all the motions........I plan to submit some diagrams and photos eventually...using real stars and demonstrating exactly how it was done...but the key is a translational motion will still produce a rotation on the NCP .....The rub is, I kept trying to tell you guys that the clue was “hidden” in that “most powerful definition of rotation known to man” ....In fact, It would have to produce a rotational effect in order for all of the motions to be "equivalent"!.............. Oh, what fun I am going to have now.....”Destruction” and “chaos” the likes of which have not been seen since the Renaissance itself..& ..It won’t take me any 400 years either!