[geocentrism] Re: acceleration calcs

  • From: Paul Deema <paul_deema@xxxxxxxxxxx>
  • To: geocentrism@xxxxxxxxxxxxx
  • Date: Tue, 18 Mar 2008 16:43:24 +0000 (GMT)

Allen D
I will not be diverted by your attempted sleight of hand tricks. Point out the 
error in my closing paragraph or forever hold to silence.
Paul D



----- Original Message ----
From: Allen Daves <allendaves@xxxxxxxxxxxxxx>
To: geocentrism@xxxxxxxxxxxxx
Sent: Tuesday, 18 March, 2008 4:16:09 PM
Subject: [geocentrism] Re: acceleration calcs


Paul....
Let me see if i can cut through all the chase in this our discussions here.
 
If the earth remained stationary wrt a distanct star but  a car on the earth 
first sitting at rest then began to accelerate by 1g due to that same distanct 
star,  would that motion be detected by your mass accelerometer in the car or 
not?    
 
There are only two posibilites: 
 
1. If not....... then please expalin to everyone what causes the tides and 
planitary bulges so we can establish the underlying physics for gravity/ 
inertia.....? 
 
2. If so......... then the only difference is scale of the effects....between a 
car laying horizonaly on the earths suface and "free falling at 1g toward a 
distant star  or a bomb hanging horizonaly to a distant star and free falling 1 
g to earth's suface....
 
The problem with your "mass and spring"  is only one of resolution or scale 
that is why I appealed to quantum and laser acclerometers/ gyros. It is not 
that the effect is not there in relaity it is just that in relaity our mass on 
a spring is not sinsitive enougph to measure what is taking place regaurdless 
of GU or HC universe.......



----- Original Message ----
From: Paul Deema <paul_deema@xxxxxxxxxxx>
To: Geocentrism@xxxxxxxxxxxxx
Sent: Tuesday, March 18, 2008 8:25:47 AM
Subject: [geocentrism] Re: acceleration calcs


Allen D
 
It may be that I just don't understand your descriptions -- heaven knows I am 
not alone and you do little to ameliorate this -- but I'm going to proceed on 
the basis that I do understand what you are saying. I'm not going to address 
your objections point by point -- that is a quagmire that I for one have been 
bogged down in more than once. I'm going to be charitable and assume that you 
still do not grasp what I'm saying about accelerometers.
 
An accelerometer is a mass suspended in some manner, such as by a spring, in a 
vehicle which is to be accelerated. Now if we were to hang this device from a 
stationary beam in a 1 'g' gravity field, and it has a mass of 1 kg, then the 
spring will be extended, coming to a halt when the spring exerts an upward 
force of 1 kg. If the accelerometer is properly calibrated, it will read 1 kg. 
If you repeat the experiment on the Moon, it will read -- roughly -- 0.166 kg. 
If we take the accelerometer and mount it in a space vehicle in free fall, it 
will read 0 kg. If we initiate a rocket burn, and the accelerometer reads -- 
while the motor is firing -- 1 kg, then we can state that our acceleration is 
equal to what we would feel standing on the Earth -- an acceleration of one 
'g'. Thus the extension of the spring is an exact analogue for the amount of 
acceleration being experienced. It relies for its operation on Newton's first 
law of motion and Hooke's law of
 elasticity.
 
There is another way we could utilise the accelerometer to determine our 
acceleration in a space vehicle. Let us assume again that we are in space in 
free fall and we are about to initiate a rocket burn. This time, instead of 
gluing our eyes to the accelerometer, we detach the 1 kg mass and place it 
outside the vehicle in free fall with velocities matched. We initiate our 
rocket burn, and with some radar or laser device we continuously measure the 
distance to the 1 kg mass. If we integrate the readings over time, we can 
calculate our acceleration.
 
Now for the crunch, the bit where our velocity changes due to acceleration by 
gravity. (Note - from a recent post from Regner, perhaps 'speed' is more 
appropriate here -- please comment if you think it appropriate. In any event, 
what I'm trying to convey is that our rate of travel increases). This time, we 
place our vehicle into elliptical orbit -- around Earth will suffice -- and as 
we pass apogee, we begin to accelerate. At this moment we place our 
accelerometer 1 kg mass outside the vehicle with velocities matched and engage 
our distance and time measuring devices. After we have passed perigee we will 
have stopped accelerating and begin decelerating. At no time from apogee to 
perigee will the 1 kg mass have fallen behind or overtaken us and this will not 
change from perigee back to apogee and so on for ever and ever amen. Despite 
acceleration and deceleration due to gravity in an elliptical orbit, our 
accelerometer will indicate no change in velocity.
 
Paul D



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