[geocentrism] Re: Uranus

  • From: "philip madsen" <pma15027@xxxxxxxxxxxxxx>
  • To: <geocentrism@xxxxxxxxxxxxx>
  • Date: Mon, 15 Dec 2008 10:38:21 +1000

No before I even look at your diagram or words, Please just answer my clear 
question repeated again. If you cannot accept this simple geometric 
explanation, then anything you say has no meaning.  
I offer it here again..  

Forget everything else I said about forces, leave energise motors et al out of 
the equation, let us treat of pure geometrical form. A simple animated diagram.

I will explain the detail. 

A weightless sphere on a shaft also weightless set at 20 degerees off vertical 
axis spins once per period P.  It is rotating. It will have a mark indicating 
the starting point, pointing at the central vertical axis. 

At the same time in the same period P the sphere attached to the shaft still 
fixed at the bottom to the vertical axis,  performs a single 360 degree orbit 
of the vertical axis . 

During this orbit it will present the same face to the central axis. 

Duriing this orbit the shaft will be seen to be rotating one spin per period P, 
quite easily at the bottom bearing point on the vertical axis.   Do you agree 
with that?

If the bottom end of the shaft is always spinning, why is the top end where the 
sphere is attached , not spinning, simply because it is made to translate in an 
orbit? Are you not making the impossible happen, ie that a solid shaft can spin 
at one end, and not at the other? 

Philip. 

  ----- Original Message ----- 
  From: allendaves@xxxxxxxxxxxxxx 
  To: geocentrism@xxxxxxxxxxxxx 
  Sent: Monday, December 15, 2008 10:23 AM
  Subject: [geocentrism] Uranus


        Phil the same principle applies to geometrical rotation without respect 
of force..The only motor/top that keeps the same side to the center is the 
motor/top that is not geometrically rotating....and even if you were on the 
orbital plate while at 100rpm you would still not see the motor/top 
rotate!...and if you stop the orbit of 100 rpm you will still not see the 
motor/top rotate!... There is no rotation....To have a pure "geometrical 
motion" it still must be relative to something else....if you are the outside 
observer you do not see the parts of the place make a progressive radial 
orientation to a point that lay in the plate, and if you are on the orbital 
plate itself you still do not see the top/ motor make a progressive radial 
orientation to a point that lay in the top/motor itself aka rotation 
.........where do you see geometrical rotation?! there is no geometrical 
rotation in any reference frame you lay claim to.....either before the orbit is 
started, while it is taking place or when it is stopped....The geometrical 
rotation is only to a common point that lay outside the tops/motors in 
question.......... You don't have relative motion with respect to anything, so 
where is the rotation?...The outside observer sees all points on the top/motor 
make a progressive radial orientation to the point that lay outside the 
top...If the top were in rotation they would see that progressive radial 
orientation during the orbit, before the orbit, and after you stopped the 
orbit, but It is not there. You are simply trying to divide something into 
parts, and call them different things, that cannot be divided or separated into 
individual geometrical parts... 









        Ok...Phil look at diagram "1 force rotational sync".png...i attached 
them all here again..........one motor/top is not energized and not rotating it 
will keep the same side facing the center of the place at all times...before 
during and after the orbit (bottommotor is spun up) of 100 RPM......The motor 
on the other side of the plate is energized and is first rotating at 100rpm 
before the orbit (bottom motor is spun up) of 100 rpm begins.......Now the 
orbit (bottom motor will spin up) of 100 rpm begins and cause the two motors to 
orbit the  center of the plate on which they are mounted to........we already 
know that the motor that has no energy and no rotation is keeping the same side 
to the center of the plate...but tell us about the other motor the one 
energized.....It is now spining at 100rpm even before we started the orbit and 
now the orbit is at 100 RPM.....now......Tell us how fast/& or how much energy 
you are going to have to increase or decrease to get the energized motor to 
keep its same side in sync with the center of the bottom plate? 

        Hint:  as with the tether ball and the synchronous orbit of mercury.( 
it keeps the same side facing the sun at all times).......there is no rotation 
or rotational force in either.... There is only a force or resistance that 
prevents a rotation, there is no rotation and no cause for a 
rotation...Rotation is prevented not sustained in mercury.... 


         
       

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