[geocentrism] Re: Tides and the moon and M-M
- From: "philip madsen" <pma15027@xxxxxxxxxxxxxx>
- To: <geocentrism@xxxxxxxxxxxxx>
- Date: Sat, 5 Apr 2008 12:30:57 +1000
Phil, There can be no "differeing gravity foces." to accelerate the water
upward if gravity pulls on everthing on the accelerometer ......Allen
Allen, when the moon is dead centre over head the net or resultant of the two
gravitational forces 180 degrees out of phase is less at that point than it is
at any other phase angle either side of top dead centre. That is what I meant
by differing gravity, or varying gravity.. Water seeks a common level due to
gravity.. It will flow from where there is no moon overhead to that area
beneath the moon.
This is proven no matter which semantic theory you want to apply to gravity.
I say the gravity is aetheric push not molecular pull. But I still call it
gravity. Its a very grave subject. a matter of grave concern. I gravitate to
my theory. Therefore if the aether over here squeezes all the water to over
there under the moon, because the moon interfered with and caused a lower
aether pressure or less gravity under the moon, then it is still all the same
thing.. The moon caused the tides by being where it is..
And don't try bringing this into it, "if gravity pulls on everthing on the
accelerometer "
You lost that argument well and truely before you started it..
Phil
----- Original Message -----
From: Allen Daves
To: geocentrism@xxxxxxxxxxxxx
Sent: Saturday, April 05, 2008 9:22 AM
Subject: [geocentrism] Re: Tides and the moon and M-M
Phil, There can be no "differeing gravity foces." to accelerate the water
upward if gravity pulls on everthing on the accelerometer (earth) at the same
time in the same way such that it prevents a detectable acceleration in free
fall....... !?
----- Original Message ----
From: philip madsen <pma15027@xxxxxxxxxxxxxx>
To: geocentrism@xxxxxxxxxxxxx
Sent: Friday, April 4, 2008 4:08:42 PM
Subject: [geocentrism] Re: Tides and the moon and M-M
Thank you Peter.. You saved me from wondering how to explain the simple
phenomena to them.. Because the water is fluid tidal flows can move under the
differeing gravity foces.
When the moon is overhead we weigh less because we are subject to two forces
one up one down and the vector difference is positive down..
Of course there will be a point somewhere between the bodies closer to the
moon where the vector forces in each direction will be equal and a mass will
have no weight. Go closer to the moon and it will fall to the moon go closer
to the earth and it will fall back to earth.. I would imagine this neutral
position would be easier to maintain than the similar experience on a piece of
iron between two magnets.. But even there, we can have a neutral position of
zero force.. not zero magnetism.. to say zero gravity is a misnomer.. we
mean zero force of gravity due to balancing forces.
Its just a big hill actually.. If we had a real road to the moon, it would be
uphill three quarters of the way, and down hill the rest of the way.
Or again if you kick a ball straight up into the air there wil be a split
second when it will have no weight, this does not mean there was no gravity..
Philip.
----- Original Message -----
From: PETER CHARLTON
To: geocentrism@xxxxxxxxxxxxx
Sent: Saturday, April 05, 2008 6:06 AM
Subject: [geocentrism] Re: Tides and the moon and M-M
As you know, I have no scientific knowledge, but it seems logical to me
that, rather than there being a "zero gravity point", that instead there is a
point where the pull of gravity from the moon, is equal to the pull of gravity
from the Earth, that is, the two forces pulling equaliy at a given point.
If you go nearer the moon, you still have the pull of gravity from the
Earth, but it is less than the increasing pull from the moon, and visa versa.
Surely, if there was a point where gravity was zero, the moon would escape
from its orbit?
Pete Charlton
----- Original Message -----
From: Bernie Brauer
To: geocentrism@xxxxxxxxxxxxx
Sent: Friday, April 04, 2008 12:04 AM
Subject: [geocentrism] Re: Tides and the moon and M-M
Statement/Question:
"It is widely accepted, although not by me, that the moon causes the
tides. It is also widely accepted, although not by me, that there exists a
zero-gravity point situated somewhere between the World and moon.
My question is this: If the ocean were situated at the zero-gravity
point, then there would be no tide. Closer to the World the pull of the World
is stronger. Closer to the moon the pull of the moon is stronger. The net
effect, this side of the zero-gravity point, is always a positive pull by the
World. Since this is equivalent to a force of gravity that produces a stronger
pull as we take the oceans further this side of the zero-gravity point, then
how does the moon produce the tides?" Dr. Neville T. Jones
Response:
"IT DOES NOT DIRECTLY, ONLY INDIRECTLY. Hooray! Iʼm so glad finally
someone else sees this issue too. Further, the tides are one of the major
reasons why I model gravity as a vibration, for The Alias Effect shows that the
position of the sun and moon has a relationship to gravity on Earth but tides
demonstrate that they are not directly related due to the whole satellites
issues as well as atmosphere. However, in vibrational gravity the positions of
CB's ( Celestial Bodies ) will affect the vibrational wave. In short, the tides
are caused by the squeezing effect of the gravity vibration, that is to say,
that there is no additional or absence of gravity force, only a uneven
squeezing effect that is a result in part due to sun/moon/background-stars
positioning ( The Alias Effect proves this ). A vibration is the only known
physical explanation that can account for that effect while producing a
non-detectable gravity force in all of its anomalies, which are not anomalies
but rather clear indicators that gravity is a vibration of aether waves. No
other known physical construct could account for all those things." Allen Daves
Jack Lewis <jack.lewis@xxxxxxxxxxxx> wrote:
I haven't yet seen anyone come with an answer to something Neville, I
think, once said regarding the point, which must exist, between the Earth and
the Moon where the gravity is zero. This being the case how is it that the Moon
controls the tides? I'm sure, I think, that there must be a simple answer.
The M-M part of the subject is to ask Regner how he is getting on with
the answering the interferometer experiments wrt a non-moving Earth?
Jack
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