[geocentrism] Re: Moon Hoax and Heliocentricity
- From: "Philip" <joyphil@xxxxxxxxxxx>
- To: <geocentrism@xxxxxxxxxxxxx>
- Date: Wed, 22 Sep 2004 18:48:55 +1000
Thanks Gary.. I promise to nut this out. I like this style. Mathmatics can
work even for fiction. Will come back when I am sober in the morn.
Phil
----- Original Message -----
From: "Gary L. Shelton" <GaryLShelton@xxxxxxxxxxx>
To: <geocentrism@xxxxxxxxxxxxx>
Sent: Wednesday, September 22, 2004 3:31 PM
Subject: [geocentrism] Moon Hoax and Heliocentricity
Hello to the Group,
I have often wanted to say to the people who point out the great Moon Hoax,
that it is mighty peculiar that a group of astronauts could leave the earth
under the assumptions of heliocentricity and make it safely back.
Let me introduce what I'm about to say by saying that I am using THE
HELIOCENTRIST STORY. I'm just trying to apply some logic to it. I am a
pure geocentrist and always will be. However, if one believes the earth
moves as we have all been taught, then what the heck were those astronauts
doing up there on Apollo 11?
The story I always heard was they left on July 16, 1969 in 1st Quarter phase
of the moon, and splashed down some eight days later. Forgetting the
radiation show-stopper for this essay, the other facts I heard as a kid when
they would invariably and irritatingly interrupt my cartoons (I'm 44 now)
were that the craft travelled at 20,000 mph and they took 84 hours to get to
the moon and another 84 hours to get back.
BUT HOW? 1st Quarter phase means (in the h-people world) that the moon is
exactly trailing the earth in the earth's orbit around the sun and therefore
travelling through space at the same or similar 66,000 mph as the earth does
around the sun. This means that as Apollo 11 left the earth for the moon at
20,000 mph, the moon was simultaneously coming to them at 66,000 mph. This
combined speed was 86,000 mph. And the distance separating the moon and the
earth is taught to us at about 250,000 miles. So I ask again: How did it
take 84 hours to get to the moon? It should have only taken 4 hours. What
were the astronauts doing all these extra 80 hours? This is a puzzle, is it
not?
Still, a bigger puzzle occurs for the return trip. The moon is moving
between 1st Quarter and Full Phases now, and the major factual change is
that the destination object, the earth, is no longer coming at the
astronauts as the moon was originally. It is in fact moving away from them.
At the very most generous, one might say the earth and moon were moving
parallel to each other at this time, as they would during Full Phase. But
the earth is clearly not heading toward the returning astronauts. (Keep in
mind I am using a simple circular path of the moon around the earth as my
basis for this hypothesis.)
So, the question is thus: How does it take the same amount of time for the
return trip as it did to reach the moon? There are very different factors
to take into account if you are a heliocentrist. It is almost laughable to
think that the astronauts could have left the surface of the moon travelling
at a puny 20,000 mph and trying to catch an earth moving at 66,000 away from
them. Wouldn't this be akin to a fast runner trying to catch a faster
moving car, that is already going highway speed and is already twelve hours'
distant from the runner when the runner takes off? How does this runner
catch the car? Likewise, how did the astronauts catch the earth?
Was it the "Slingshot Method"? (Does anyone else recall hearing all about
this at the time?) Those chalkboard drawings they showed seem so campy in
retrospect.
Can heliocentrists provide adequate answers? I doubt it. Geocentrists
probably can't either, however. I believe the simple truth is that we never
went to the moon with Apollo.
I know this was a bit off-topic, though I hope permissibly so. I also hope
it made sense.
Thanks you for reading it.
Sincerely to the group,
Gary Shelton
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