# [geocentrism] Re: Geosynchronous satellites paper

• From: "Jack Lewis" <jack.lewis@xxxxxxxxxxxx>
• To: <geocentrism@xxxxxxxxxxxxx>
• Date: Wed, 18 Jul 2007 18:41:56 +0100

```Dear Paul,
Why is the transfer orbit elliptical and how do we know this? In other words
can this be worked out experimentally?

Jack
----- Original Message -----
From: Paul Deema
To: Geocentrism@xxxxxxxxxxxxx
Sent: Wednesday, July 18, 2007 6:22 PM
Subject: [geocentrism] Re: Geosynchronous satellites paper

Robert B

I find maths tedious if I already know the answer so I have not seriously
waded through your post From Robert Bennett Tue Jul 17 03:31:26 2007, but
orbit' (you did offer it as a viable alternative) and got 40000+ hits. Top of
the list -- wikipedia! (If you don't like this one, I'm sure the next one will
give the same answer, and the next, and the next ... ). The site gives all the
equations necessary to understand the problem, several of which you have
already quoted to me, but they come to a decision opposite from yours and in
line with mine.

Here's a teaser.

(Extract from ... )

http://en.wikipedia.org/wiki/Hohmann_transfer_orbit

Explanation

The Hohmann transfer orbit is one half of an elliptic orbit that touches both
the orbit that one wishes to leave (labeled 1 on diagram) and the orbit that
one wishes to reach (3 on diagram). The transfer (2 on diagram) is initiated by
firing the spacecraft's engine in order to accelerate it so that it will follow
the elliptical orbit; this adds energy to the spacecraft's orbit. When the
spacecraft has reached its destination orbit, its orbital speed (i.e., orbital
energy) must be increased again in order to make its new orbit circular; the
engine is fired again to accelerate it to the required velocity.

(Plus attached illustration).

Capitulate yet?

Paul D

PS I don't know if Philip M would be impressed with being lumped in with me